A square foundation is 1.5 m X 1.5 m in plan. Given the soil properties supportingthe foundation are, friction angle =20°; cohesiveness15.4 kN/m; unit weight!3!=18 kN/m. By assuming the depth of the foundation is 1 meter and that generalshear failure occurs in soil, determine the allowable gross load on the foundationwith a factor of safety of 4.

Data is as given General shear failure

A square foundation is 1.5 m X 1.5 m in plan. Given the soil properties supporting the foundation are, friction angle =20°; cohesiveness = 15.4 kN/m²; unit weight =18 kN/m. By assuming the depth of the foundation is 1 meter and that general shear failure occurs in soil, determine the allowable gross load on the foundation with a factor of safety of 4.

A square foundation is 1.5 m X 1.5 m in plan. Given the soil properties supporting the foundation are, friction angle =20°; cohesiveness = 15.4 kN/m²; unit weight =18 kN/m. By assuming the depth of the foundation is 1 meter and that general shear failure occurs in soil, determine the allowable gross load on the foundation with a factor of safety of 4.

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter5: Ultimate Bearing Capacity Of Shallow Foundations: Special Cases

Section: Chapter Questions

Problem 5.1P

See similar textbooks

Similar questions

Calculate the ultimate bearing capacity of a 2 m wide strip foundation embedded 2 m below the ground surface in soil with a saturated unit weight of 20 kN/m3. Dry unit weight of 18&N /m The water table is at the foundation level. The friction angle is 30°. 1. Calculate the bearing capacity of the foundation. 2. The design load on the foundation is 500 kPa. Comment on the safety of the foundation.
Problem.№₂3 - The plan of a mat foundation is shown in Figure. Calculate the soil pressure at points A, B, C, D, E, and F. (Note: All column sections are planned to be 0.5 m 3 0.5 m.) All loads shown are factored loads according to ACI 381-11 (2011). 550 KN 2000 KN 5.25 m 2000 KN 550 kN F *K 0.25 m G H 10 m ! B i 660 kN 2000 KN 10 m 2000 KN 660 kN E 600 KN 1600 KN 5.25 m 10 m 1600 KN 470 kN C D *K 0.25 m 9 m 9 m 9 m 0.25 m 0.25 m
Calculate the nominal bearing capacity of the shallow foundation using the Vesić formula. The foundation base is embedded at a depth of 1.5 ft under the soil surface. The water table is at the soil surface. The total unit weight of the soil is 109 lb/ft3, and the unit weight of the concrete is 145 lb/ft3 . Therefore, the undrained shear strength of soil is cu=2000 lb/ft2 . The width of the foundation is 10 ft, and the length is 14 ft, while the foundation base height is 1 ft. A vertical force acts at the foundation's axis on the top of the foundation base, P=450 kips, and a horizontal force, H=50 kips, acts perpendicular to the foundation length at 2 ft from the foundation bottom.
Question one: A square foundation (BxB) has to be constructed as shown in Figure. Assume that Y=17 kN/m3, Ysat = 20 kN/m3 , D=34, DF 2 m, and D = 1 m. The gross allowable load, Qall, with FS = 3 is 700 kN. Determine the size of the foundation. %3D Water D Y. 6,'= 0 table Yat D. BYB
Q2: Compute the total stresses, which induced from geostatic stress and increase vertical stress from circular foundation under points A and B to 3 and 6 m depth from the base of the foundation. The foundation was constructed at 2.0 m below the natural ground level (NGL). The surface load intensity is 330 kN/m². R1= 4, (calculate R2 from the drawing, do not assume it). Assume any other parameter you need in your answer. Aqs net
A shallow continuous foundation is to be constructed on a soil under the ground'. surface as shown in the figure below. Determine the gross allowable bearing capacity with a factor of safety FS = 3. All dimensions in meter. II. Comment of the effect of placing the footing at the ground surface (i.e. Dr= 0) on the computed allowable bearing capacity. Take Neg as 5. 2.8 1.4 I G.S. 30 1.4 Yson = 17.7 kN/m = 30° C= 40 KN/m?
A column foundation (Figure 16.23) is 3 m 2 m in plan. Given: Df = 1.5 m, =25, c = 70 kN/m2. Using Eq. (16.9) and FS = 3, determine the net allowable load [see Eq. (16.16)] the foundation could carry. FIG. 16.23
In Problem 7.1, if there was no bedrock present for at least 12.0 ft below the foundation, what would the ultimate bearing capacity be? 7.1 A 7.5 ft wide rough continuous foundation is placed in the ground at 3.0 ft depth. There is bedrock present at 3 ft depth below the bottom of the foundation. The soil properties are c′ = 210 lb/ft2, ϕ′ = 25°, and γ = 115.0 lb/ft3. Determine the ultimate bearing capacity of the foundation.
For the following cases, determine the allowable gross vertical load-bearing capacity of the foundation. Use Terzaghi’s equation and assume general shear failure in soil. Use FS = 4. Parameters for Problem 6.1
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]
o T ☺ ť Q2: A ring foundation having load equal to 400kPa is resting on a saturated clay soil layer, the groundwater level is at the natural ground surface. The outer diameter of the foundation ring is 8m. Find the inner radius of the ring foundation if the total stress at a point located 4m beneath the center of the ring foundation equal to 251kPa, knowing that the saturated unit weight of the clay is 16kN/m'. (Use the below formula) Solution:- Aoz = q مر ر ل لأعلى لاستعراض الفلاتر إضافة شرح.. . mum <
QUESTION 5 A 1.8 m x 2.5 m foundation is shown in Figure. If the load eccentricity B 0.45 m and e 0.30 (two-way), determine the allowable load Qall. = 1.6 m ↑ B x L = 1.8 m x 2.5 m c = 0 kN/m² = 34° = 18 kN/m³ Yn Gs = 3