College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- 1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 Parrow_forwardThe following diagram shows a solid insulating sphere with a radius "a" and a charge +3Q surrounded by a spherical conducting shell with inner radius "b", and outer radius "c", and a net charge -20. What is the electric field (direction and magnitude) in the region where aarrow_forwardThe figure gives the magnitude of the electric field inside and outside a sphere with a positive charge distributed uniformly throughout its volume. The scale of the vertical axis is set by Es = 4.3 × 107 N/C. What is the charge on the sphere?arrow_forwardYou are working as an intern for a meteorological laboratory. You are out in the field taking measurements with a device that measures electric fields. You measure the electric field in the air immediately above the Earth's surface to be 194 N/C directed downward. (Assume the radius of the Earth is 6.37 x 106 m.) (a) Determine the surface charge density (in C/m²) on the ground. C/m² (b) Imagine the surface charge density is uniform over the planet. Determine the charge (in C) of the whole surface of the Earth. C (c) Determine the Earth's electric potential (in V) due to the charge found in (b). V (d) Determine the difference in potential (in V) between the head and the feet of a person 1.50 m tall. (Ignore any charges in the atmosphere.) Varrow_forwardNCS-1 A non-conducting sphere of radius R=0.300m has a total charge q-100μC that is evenly distributed throughout its volume. a) Find the charge within a radius of r=0.100m. Hint: first find the volume charge density p. b) Find the electric field strength at r=0.100m. c) Find the charge within a radius of r-0.200m. d) Find the electric field strength at r-0.200m. e) Find the charge within a radius of 1-0.300m. f) Find the electric field strength at r-0.300m. g) How does E change with increasing radius? Rarrow_forwardA thin, square, conducting plate 47.0 cm on a side lies in the xy plane. A total charge of 3.50 10-8 C is placed on the plate. You may assume the charge density is uniform. (a) Find the charge density on each face of the plate. C/m2(b) Find the electric field just above the plate. magnitude N/C direction (c) Find the electric field just below the plate. magnitude N/C directionarrow_forwardA thin, square, conducting plate 49.0 cm on a side lies in the xy plane. A total charge of 3.70 x 10-8 C is placed on the plate. You may assume the charge density is uniform. (a) Find the charge density on each face of the plate. C/m² (b) Find the electric field just above the plate. magnitude N/C direction -Select--- ✓ (c) Find the electric field just below the plate. magnitude N/C direction -Select--- ✓arrow_forwardA flat surface of area 3.10 m² is rotated in a uniform electric field of magnitude E = 6.65 x 105 N/C. 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What is the direction of the electric field E created by the disk at point P. Direction: 3. Write the expression of the electric filed E created by the disk at point P. Ē =< [N/C] 4. Find the magnitude of the electric field E created by the disk at the point P located at distance 8 m from thearrow_forwardQuestion 2 A 43.8 cm long rod has a nonuniform charge density given by the equation A(z) = Ae-2/b, where A = 2.50 nC/cm and b= 14.0 cm. What is the total charge on the rod? Hint: This problem requires integration! + + + + ++ Total charge on rod: +arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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