A speaker is playing a sound of consistent amplitude at a distance of 3.0 m from your ear. It plays the sound for 5.0 seconds. You measure the sound intensity at the location of your ear to be 1.7 x 10-7 W/m². 1 If your eardrum has a surface area of 85 mm2 (= 8.5 x 10-5 m²), how much energy is incident on your eardrum in the 5.0 seconds that the speaker is playing? Your answer should be in units of J. Express your answer in scientific notation. Type your answer... 2 If you move the speaker so that it is now 9.0 m from your ear, what will be the sound intensity at the location of your ear? Assume the sound wave being output from the speaker is a spherical wave. Your units should be W/m2, but do not include the units in the answer box. Express your answer in scientific notation.

icon
Related questions
Question
**Title: Understanding Sound Intensity and Energy Impact on the Eardrum**

---

### Problem 1: Calculating the Energy Incident on the Eardrum

A speaker plays a sound at a consistent amplitude from a distance of 3.0 meters. It produces sound for a total duration of 5.0 seconds. At your ear's location, the measured sound intensity is \(1.7 \times 10^{-7} \, \text{W/m}^2\).

**Question:**
- If your eardrum has a surface area of 85 mm\(^2\) (\(= 8.5 \times 10^{-5} \, \text{m}^2\)), how much energy is incident on your eardrum during the 5.0 seconds of sound playback?

Your answer should be provided in units of Joules (J) and expressed in scientific notation.

---

### Problem 2: Sound Intensity at a Greater Distance

**Question:**
- If the speaker is moved so that it is now 9.0 meters from your ear, what will the sound intensity at your ear's location be? Assume the sound wave emitted from the speaker is a spherical wave.

Your answer should be in units of \(\text{W/m}^2\), expressed in scientific notation, without including the units in the answer box.

---

These problems will help you understand the relationship between distance, sound intensity, and the energy received by a surface, such as the eardrum. Analyzing such interactions is essential for comprehending principles of acoustics and sound wave behavior.
Transcribed Image Text:**Title: Understanding Sound Intensity and Energy Impact on the Eardrum** --- ### Problem 1: Calculating the Energy Incident on the Eardrum A speaker plays a sound at a consistent amplitude from a distance of 3.0 meters. It produces sound for a total duration of 5.0 seconds. At your ear's location, the measured sound intensity is \(1.7 \times 10^{-7} \, \text{W/m}^2\). **Question:** - If your eardrum has a surface area of 85 mm\(^2\) (\(= 8.5 \times 10^{-5} \, \text{m}^2\)), how much energy is incident on your eardrum during the 5.0 seconds of sound playback? Your answer should be provided in units of Joules (J) and expressed in scientific notation. --- ### Problem 2: Sound Intensity at a Greater Distance **Question:** - If the speaker is moved so that it is now 9.0 meters from your ear, what will the sound intensity at your ear's location be? Assume the sound wave emitted from the speaker is a spherical wave. Your answer should be in units of \(\text{W/m}^2\), expressed in scientific notation, without including the units in the answer box. --- These problems will help you understand the relationship between distance, sound intensity, and the energy received by a surface, such as the eardrum. Analyzing such interactions is essential for comprehending principles of acoustics and sound wave behavior.
Expert Solution
Step 1

Intensity  of sound is inversely  proportional to square of distance from the source 

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer