A spacecraft launches from the International Space Station and flies directly away from the earth at a constant speed of 270 miles per hour. The International Space Station is 254 miles above the Earth. The spacecraft's distance from the Earth t hours after launch is given by D = 254 + 270t miles. Explain in practical terms the meaning of the initial value and growth rate. In practical terms this means that "When the spacecraft launched, it was away from Earth and its distance away from the ---Select--- Earth is increasing at a rate of ---Select--- 6 ".

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter10: Exponential And Logarithmic Functions
Section10.5: Solve Exponential And Logarithmic Equations
Problem 10.87TI: Researchers recorded that a certain bacteria population grew from 100 to 500 in 6 hours. At this...
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A spacecraft launches from the International Space Station and flies directly away from the earth at a constant speed of 270 miles per hour. The International Space Station is 254 miles above the Earth. The spacecraft's distance from the Earth t hours after launch is given by D = 254 + 270t miles. Explain in practical terms the meaning of the initial value and growth rate.

 

A spacecraft launches from the International Space Station and flies directly away from the earth at a constant speed of 270 miles per hour. The International
Space Station is 254 miles above the Earth. The spacecraft's distance from the Earth t hours after launch is given by D = 254 + 270t miles. Explain in practical
terms the meaning of the initial value and growth rate.
In practical terms this means that "When the spacecraft launched, it was
---Select---
O away from Earth and its distance away from the
Earth is increasing at a rate of
---Select---
O ".
Transcribed Image Text:A spacecraft launches from the International Space Station and flies directly away from the earth at a constant speed of 270 miles per hour. The International Space Station is 254 miles above the Earth. The spacecraft's distance from the Earth t hours after launch is given by D = 254 + 270t miles. Explain in practical terms the meaning of the initial value and growth rate. In practical terms this means that "When the spacecraft launched, it was ---Select--- O away from Earth and its distance away from the Earth is increasing at a rate of ---Select--- O ".
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