A solution of sodium thiosulfate was standardized by dissolving 0.1906 g KIO3 (214.00 g/mol) in water, adding a large excess of KI, and acidifying with HCI. The liberated iodine required 48.92 mL of the thiosulfate solution to decolorize the blue starch/iodine complex. Calculate the molar concentration of the Na2S2O3. Express your answer with 3 decimal places

You were assigned to assay a product sample of milk of magnesia. A 0.600-g sample was reacted with 25.00 mL 0.10590 N H2SO4 . The excess unreacted acid in the solution required 13.00 mL of 0.09500 N NaOH when titrated to reach the methyl red end point. Determine the dosage strength of the product in terms of % Mg(OH)2 content. Type your answer in 2 decimal places, numbers only.

For a 50ml beaker, 0.4532g of pure iron III oxide was weighed, to which 1 ml of a concentrated hydrochloric acid solution was added and then 20 ml of deionized water was added to the beaker. After mixing, the resulting solution was transferred to a 50.00 ml flask and the volume was made up with deionized water. Then 15ml of this solution into a second beaker to which 10ml of an iron iii chloride solution of 0.200 M concentration was added. Calculate the final concentration of the iron iii cation solution expressed in mol/L and in g/L, considering that the volumes are additive.

Suppose the Kc value for Cobalt (II) hexahydrate is 6.80 and suppose upon heating the solution turned pink.  If a group of student started mixed 10.5 mL of a 1.25 M [Co(H2O)6]2+(aq) solution with 12.5 mL of a 1.55 M solution of NaCl(aq) with 15.25 mL of a 1.39 M [CoCl4]-2(aq) solution then what color is the solution at equilibrium?   [Co(H2O)6]2+(aq)  +  4 Cl-(aq)      [CoCl4]-2(aq)  +  6 H2O(L)   Multiple choices   pink   purple   green   black   orange   brown   blue   colorless   yellow   gray   red   green

A solution of malonic acid (H2C3H2O4) with a known concentration of 0.500 M H2C3H2O4 is tirated with a 0.255 M KOH solution. How many mL of KOH are required to reach the second equivalence point with a starting volume of 60.0 mL H2C3H2O4, according to the following balanced chemical equation: H2C3H2O4 + 2 KOH---> K2C3H2O4 + 2 H2O