A Solid Steel bar of diameter 60mm and length 50mm is placed inside an aluminum cylinder of Inside -meter 70mm and out side diameter Ilomm, Compressive load of looo la is applied on the assembly rol the stresses in the bar and the cylinder? take st = 200 G Pa and EA1 = 70 Gra.

SITUATION. A steel plate ABCD of thickness t = 5mm is subjected to uniform stresses: = 100 MPa 0₂ = -60 MPa. Ox E =200GPa, v= 1/3 a = 160mm and b = 200 mm Calculate the change in thickness (mm). -0.0023 mm 0.0023 mm O O 0.0045 mm - 0.0045 mm Ł B AL C D X

2. Locate the centroid of the composite figure. -1.00in. 1 2 R.625in. 2.00in. 3 .50in. y .625in.- 1.375in. 2.00in.

The pin-connected assembly consists of aluminum rods (1) and (2) and steel rod (3). The aluminum rods each have a diameter of 11 mm and an elastic modulus of E = 78 GPa. Thesteel rod has a diameter of 16 mm and an elastic modulus of E = 200 GPa. Assume a = 4.1 m, b = 1.2 m, and c= 1.2 m. What is the magnitude of load P that is necessary to displace point A 12 mm to the left? (1) P (3) B (2) Answer: P = 117.7 kN

Flexibility Method: Beams and Frames with more than one redundant, and a Truss with one redundant. Solve the following 3 problems: Problem 1: Given: The following beam has fixed supports at A and B, and has a constant EI. W Required: Evaluate the two vertical reactions (Ay and By) and the two moment reactions (MA and MB). Neglect Ax and Bx. Draw the Shear Diagram Draw the Moment Diagram Sketch the deflected shape Hint: In this problem, it looks like it is indeterminate to the third degree, but let's neglect axial effects. By neglecting axial effects, we are not considering the horizontal force equilibrium equation (i.e., we neglect sum of fores in the x-direction). Thus, we neglect the two horizontal reactions (Ax and Bx). Therefore, the problem simplifies as follows: We are left with 2 equilibrium equations (i.e., sum of forces in the y-direction and sum of moments). So, you have 2 equations and 4 unknowns: Ay, MA, By, and MB. Thus, we need to come up with 2 more equations..these are…

1. The assembly has the diameters and material makeup indicated. If it fits securely between its fixed supports when the temperature is T; = 70°F, determine the average normal stress in each material when the temperature reaches T2 = 130°F. 304 Stainless steel - 2014-T6 Aluminum -C 86100 Bronze A 12 in. 8 in. D C 4 in. -4 ft- 6 ft- 3 ft

#2 will upvote to anyone who will answer

The column above is subjected to axial loading only. Assume the following: • E= 29000 ksi G = 10000 ksi • = 986 in4 A = 60 in? • L= 20 ft • Grade 60 steel (60 ksi yield stress) • The column is fixed at the top and pinned at the bottom Which of the following is closest to the maximum normal stress the column can support (before yielding or buckling)? 167 ksi 24 ksi 42 ksi 60 ksi

What maximum load P can be applied without exceeding an allowable stress of 70 MPa for aluminum or 120 MPa for steel? Can a larger load P be carried if the length of the aluminum rod is changed. the length of the steel portion being kept the same? If so, determine this length

Please solve this question and provide solution