How do I find the minimum? The answer is not 2.68 and it also was not 3.3. Question 5 of 6>O Attempt 18A solid 0.5150 kg ball rolls without slipping down a trackFeedbacktoward a vertical loop of radius R = 0.7350 m. WhatThe ball is rolling without slipping,minimum translational speed vmin must the ball have when ittherefore its angular speed w at anyis a height H1.111 m above the bottom of the loop inmoment is related to its translationalorder to complete the loop without falling off the track?speed v by w =vlr, where r is theAssume that the radius of the ball itself is much smaller thanHradius of the ball.the loop radius R. Use g9.810 m/s? for the accelerationdue to gravity.In order for the ball not to fall off theloop, the normal force exerted on theball by the loop must always bepositive. For this to be true at the top ofthe loop, Newton's second law revealsthat the magnitude of the centripetal2.68Umin =m/sforce on the ball must be greater thanIncorrectthe weight of the ball.

At the loop, two forces will act. One will be weight due to gravity and the other will be normal…

A solid 0.5150 kg ball rolls without slipping down a track < Feedback toward a vertical loop of radius R = 0.7350 m. What The ball is rolling without slipping, minimum translational speed vmin must the ball have when it therefore its angular speed æ at any is a height H = 1.111 m above the bottom of the loop in moment is related to its translational order to complete the loop without falling off the track? speed v by w = v/r, where r is the Assume that the radius of the ball itself is much smaller than H radius of the ball. the loop radius R. Use g = 9.810 m/s² for the acceleration due to gravity. In order for the ball not to fall off the loop, the normal force exerted on the ball by the loop must always be positive. For this to be true at the top of the loop, Newton's second law reveals that the magnitude of the centripetal force on the ball must be greater than 2.68 Umin = m/s Incorrect the weight of the ball.

A solid 0.5150 kg ball rolls without slipping down a track < Feedback toward a vertical loop of radius R = 0.7350 m. What The ball is rolling without slipping, minimum translational speed vmin must the ball have when it therefore its angular speed æ at any is a height H = 1.111 m above the bottom of the loop in moment is related to its translational order to complete the loop without falling off the track? speed v by w = v/r, where r is the Assume that the radius of the ball itself is much smaller than H radius of the ball. the loop radius R. Use g = 9.810 m/s² for the acceleration due to gravity. In order for the ball not to fall off the loop, the normal force exerted on the ball by the loop must always be positive. For this to be true at the top of the loop, Newton's second law reveals that the magnitude of the centripetal force on the ball must be greater than 2.68 Umin = m/s Incorrect the weight of the ball.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotation Of A Rigid Object About A Fixed Axis

Section: Chapter Questions

Problem 10.3OQ: A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s2. At different...

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