A solenoid is made from a 25-m length of wire of resistivity2.3 * 10-8 Ω # m. The wire, whose radius is 2.1 mm, is wrappeduniformly onto a plastic tube 4.5 cm in diameter and 1.65 m long.Find the emf to which the ends of the wire must be connected toproduce a magnetic field of 0.015 T within the solenoid.

Q: Two very long, parallel wires are separated by d = 0.065 m. The first wire carries a current of I1 =…

A: Given:distance between the wires, d = 0.065 mcurrent in wire 1, I1 = 0.75 Acurrent in wire 2, I2 =…

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A: Given  Current I1=2A I2=3A distance between them d=2m

Q: It is desired to construct a solenoid that will have a resistance of 5.45 Ω (at 20°C) and produce a…

A: Given that, Resistance = 5.45 Ω Temperature = 200C  Magnetic field = 4.00×10-2 T Current = 4.80 A…

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Q: Two long, parallel conductors, separated by 14.0 cm, carry currents in the same direction. The first…

A: (a) The magnitude of the magnetic field created by I1 at the location of I2 is, B12=μ0I12πa=4π×10-7…

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A: Voltage is produced perpendicular to current and field. This voltage is hall voltage. The effect…

Q: Problem 1: Two long thin parallel wires are 0.1 m apart and each wire carries a current of 12 A. The…

A: The magnetic field at point P B=−(1.4×10−5T)i−(4.8×10−5T)j​.Explanation:

Q: It is desired to construct a solenoid that will have a resistance of 5.45 (at 20°C) and produce a…

A:

Q: It is desired to construct a solenoid that will have a resistance of 4.80 N (at 20°C) and produce a…

A: Resistance = 4.8 ohm resistivity= 1.7 x 10-8 ohm.m radius of wire= 0.25 mm Current =3.9 A…

Q: The Emf is equal to ξ=46.1V, R=36.4Ω. What is the current flowing through R1 (in A)?

A:

Q: It is desired to construct a solenoid that will have a resistance of 5.75 (at 20°C) and produce a…

A: Resistance = 5.75 Temperature = 200C Magnetic field = Current = 4.85 ADiameter of wire= 0.500…

Q: A length of copper wire carries a current of 11 A, uniformly distributed through its cross section.…

A: Given,Current I=11Awire diameter d=2.1mmradius r=2.12=1.05mm

Q: A wire is coiled with a cross sectional area of 0.71m^2. It moves through a 1.6T magnetic field in…

A: Given value--- Area = 0.71 m². magnetic field = 1.6 T. time = 2.85 sec. current = 6 Amp. resistance…

Q: A length of copper wire carries a current of 11 A, uniformly distributed through its cross section.…

A: Given: The current is I=11 A The diameter of the wire is 2.3 mm The resistance is 4.5 Ω/km

Q: to support an energy density of 1.00 J/m^3 within the volume of the solenoid, how much current must…

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Q: In the August 1992 space shuttle flight, only 250 m of theconducting tether considered in Example…

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Q: U1 25V R1 50 R6 39 www 250 R2 www 375 www R5 R3 150 U2 2.5 ww R4 27.5 www

A: Determine the net resistance in series. Determine the net voltage.

Q: R₂ www ww R₂ 8₂1- 1. In the given figure above, the ideal batteries have emfs 1-10.0V and…

A: Given: The emf of the first battery is, ε1=10 V. The emf of the second battery is, ε2=0.500ε1. The…

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Q: In the figure below, a metal rod is forced to move with constant velocity along two parallel metal…

A: Dear student, this question contains more than three sub-parts. We will answer first three…

Q: solenoid of 35 turns and area 20 cm2 has its ends connected together though a resistance of 5 Ohms.…

A: Given  number of turns N = 35  area A = 20 cm2 = 20 × 10-4 m2  resistance R = 5 ohm  magnetic flux…

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Q: Figure P20.29 shows a bar of mass m = 0.200 kg that can slidewithout friction on a pair of rails…

A: The below figure indicates the magnetic field of the bar,

Q: The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.06…

A: I1 = 4.06 mA = 4.06 × 10- 3 A I2 = 6.90 mA = 6.90 × 10- 3 A d1 = 2.40 cm = 2.40 × 10- 2 m d2 = 5.32…

Q: 2a. Find the magnetic field the iron wire exert on the copper wire in μT. (For this part only,…

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Q: A copper wire with a square cross-section (side length 5.00 µm) is next to an iron wire with a…

A: Given, The copper wire with a square cross-section ,side length, L = 5.00 µm = 5×10-6 m The iron…

Q: Use Ampere's Law to calculate the value of the line integral Φ B ds in a wire loop where the…

A: Here is the step-by-step explanation We will use Ampere's Law for a wire loop where the direction of…

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Q: A square-shaped solenoid with a diameter of 0.2032 mm, is 3.5 meters tall, with 0.75-m long sides.…

A: The given values are,

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A: We know that magnetic field inside solenoid is given by B= μ0NLI

Q: A biophysics experiment uses a very sensitive magnetic field probe to determine the current…

A: Given: Peak field strength = 8 x 10-12 T Distance = 1.0 mm

Q: It is desired to construct a solenoid that will have a resistance of 4.45 Ω (at 20°C) and produce a…

A:

Q: A piece of copper wire has a resistance per unit length of 5.40 × 10³/m. The wire is wound into a…

A: Write the provided data.Here,  is the resistance per unit length, r is the radius, and V is the…

Q: An 820-turn wire coil of resistance 24.0 Ω is placed on top of a12 500-turn, 7.00-cm-long solenoid,…

A: A). Formula to calculate the self-inductance of the solenoid coil is,

Electromagnets

The word "electromagnet" is composed of two words, ‘electro’ and ‘magnet’. It is a type of magnet in which an electric current helps in the generation of a magnetic field. Electromagnets usually consist of two major parts, wire and a coil around which the wire is wound. This is called a solenoid. When an electric current is allowed to pass through the coiled wire, the electric current produces a magnetic field. This magnetic field is present only when current is passing through the wire.