A smooth can C, having a mass M = 3 kg, is lifted from a feed at A to a ramp at B by a rotating rod. If the rod maintains a constant angular velocity of 0 = 0' = 0.5 rad/s, determine the force which the rod exerts on the can at the instant 0= 30°. Neglect the effects of friction in the calculation and the size of the can so that r= 2bcos0 where b 600 mm. The ramp from A to B is circular, having a radius of b.

(b) The water is siphoned out of the tank shown in Figure 4 (b). Determine the flow rate from the tank and the pressures at points (1) and (2).

Select the correct statements regarding the addition of moments.  (Select 3)    Moments have directions, so a negative value implies it is along the opposite direction from the reference direction.            All the moments need to have the same reference point/pivot in order to add together.            Calculate each moment by multiplying each force with its distance to the reference point, and add all values together, regardless of their direction.            You have to define the reference direction first, either clockwise or counter-clockwise.

Q3/ Choose the correct option:-

Define the international system of units.

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Q1 (а) A tall standpipe as shown in Figure Q1(a) with an open top has an inner diameter 7 d=2.1 m and wall thickness t= 20 mm, Given the weight density of water y = 9.81 kN/m³ and water pressure is p = y h, calculate the height h of water that will produce a circumferential stress of 12 MPa in the wall of the standpipe. (i) (ii) Calculate the axial stress in the wall of the tank due to the water pressure.

Part I. Shorter problems focused on the fundamentals a. For the image at the right, the coordinate angles are a = 57°, ẞ= 121°, y=49°, and the point along a-a is (15,-6,3). What is the angle between lines a-a and b-b? Z b-b B LL F a (x,y,z) a-a Y b. If the magnitude of the force, F-3121bf, what is the magnitude projected along the a-a axis? y

are you sure it's not c?, can you show with diagrams

The horizontal component of Force F1 (unit is in N), H1= The vertical component of Force F1 (unit is in N), V1 = The horizontal component of Force F2 (unit is in N), H2= The vertical component of Force F2 (unit is in N), V2 = The horizontal component of Force F3 (unit is in N), H3= The vertical component of Force F3 (unit is in N), V3 = The vertical component of Force F4 (unit is in N), V4 = The horizontal component of Force F5 (unit is in N), H5= The vertical component of Force F5 (unit is in N), V5 = The horizontal component of Force F6 (unit is in N), H6= The vertical component of Force F6 (unit is in N), V6 = The sum of horizontal force component for the given system (unit is in N),begin inline style sum for H of end style = The sum of vertical force component for the given system (unit is in N),begin inline style sum for V of end style = The resultant of the given force system is (unit in N), R = The direction of Resultant Force is = Short Answer question