1c A small signal equivalent circuit of single common-emitter amplifier isshown in Figure Q1.b with quiescent collector current of 5 mA and a totalof 1 k. The transistor parameters are ß = 100, r = 200, Rs =286, C₁ = 2 pF, fr = 200 MHz.1) Deduce the values of 9m,Cfß.2) Calculate the low-frequency voltage gain Vo/Vs.1[Hint: fr = Bfpi f = 2 (G+Cu)fß:VsRsbV beIbb'₁₂C₁=C₁=ITFigure Q1.bgmV 2roC₂Cs Rc RL

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A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are = 100, r = 200, Rs = 2860, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, C fß. 2) Calculate the low-frequency voltage gain V/V. 1 [Hint: fr = BfBi ÍB = 2(C+Cu) fB Vs Rs b ľb V be C₂ Cs Rc RL 50G₁=c=1v₂ Dan Doa compa gmVr b' Figure Q1.b

A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are = 100, r = 200, Rs = 2860, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, C fß. 2) Calculate the low-frequency voltage gain V/V. 1 [Hint: fr = BfBi ÍB = 2(C+Cu) fB Vs Rs b ľb V be C₂ Cs Rc RL 50G₁=c=1v₂ Dan Doa compa gmVr b' Figure Q1.b

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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