A small current loop is placed near the end of a large magnet as shown. 1. Draw vectors to show the magnetic force on each side of the loop. What is the net effect of the magnetic forces exerted on the loop? vloe 2. Suppose that the loop were to rotate until oriented as shown.
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- complete solution for upvote pls. help me understand dis. accurate answer.f Salem Contact and Non-Contact Forces 1. Fill in the blanks. a. is a force between two objects (or an object and a surface) that is in contact with one another. is an attractive force between any two objects and causes objects to accelerate downward, towards the center of the Earth. A is experienced by any magnetic material in a C. magnetic field. It is an attractive and repulsive force (push and pull) d. An object that is being stretched experiences a e. An object at rest on a surface experiences f. Two objects sliding past each other experience g. An object moving through the air experiences a type of friction that slows falling objects. which is h. A is a force that can act between two objects that are not physically touching each other. The attractive and repulsive force (push and pull) between charged particles of matter is an is a force that exerted on an object by a person j. An or another object. 2. Circle the answers that are correct for each question. a. The factors that…Identify the object that would not experience force due to a magnet? Select one: a. Water b. Nail c. Screw d. scissor
- Near the surface of the earth, a magnet is embedded into the ceiling of a room. Another magnet is hanging at rest near the ceiling due to the magnetic force and does not make contact with anything. The hanging magnet has a mass of 900 g with its north pole facing the magnet on the ceiling and its south pole facing downwards. 1-Sketch a free-body diagram of the hanging magnet. 2- Determine the magnetic force on the hanging magnet. 3-Sketch the magnetic field between the two magnets.(a) A cosmic ray proton moving toward the Earth at 5.00107m/s experiences a magnetic force of 1.701016N. What is the strength of the magnetic field it there is a 45° angle between it and the proton’s velocity? (b) Is the value obtained in part (a) consistent with the known strength of the Earth’s magnetic field on its surface? Discuss.(a) What is the force per meter on a lightning bolt at the equator that carries 20,000 A perpendicular to the Earth's 3.00105-T field? (b) What is the direction of the force it the current is straight up and the Earth’s field direction is due north, parallel to the ground?
- A yoga teacher tells her students to imagine their hands are magnets pulling on each other. What are the problems with this metaphor? What is a better metaphor?part 1- What is the magnetic force on the top side? If the magnetic force is in the −y-direction, enter a negative value. Answer in units of N. Part 2- What is the magnetic force on the bottom side? If the magnetic force is in the −y-direction, enter a negative value. Answer in units of N. Part 3-What is the magnetic force on the left side? If the magnetic force is in the −x-direction, enter a negative value. Answer in units of N. Part 4- What is the magnetic force on the right side? If the magnetic force is in the −x-direction, enter a negative value. Answer in units of N. Part 5- What is the net magnetic force on the loop? Answer in units of N.Working the Problem 1. Use energy conservation to determine an expression for the speed of the charged particles as they exit the gun: APE = AKE qAV=1/2mv² (assume v₁ = 0) V=GAV Solve this for the speed of the particles. 2. The magnetic force acting on the particles can also be expressed as centripetal force: FB m q.v.B=m.. 9.B = m.v r Solve this form- m = q ト Вуг M AV 3. Substitute your equation for the particle speed into the second equation to develop a final expression for /m. Your equation for a/m should only contain the measurable quantities in the experiment (AV, B, & r). 2
- 1. Same situation as in the previous two problems this time the magnet s mass is 4.56 kg and the magnetic force pulling it to the right is 117.2 N. The length of the cord is 1.97 m, and the ceiling is 2.68 m above the floor. Suppose that you cut the cord and the magnet falls to the floor while still being pulled to the right by the force of 117.2 N. How long will it take the magnet to hit the floor? 2. Same situation as in the previous problem this time the magnet has mass 7.30 kg, the force pulling it to the right is 114.0 N, the cord has length 1.05 m and the ceiling is 2.70 m above the floor. How far to the right of its start point will the magnet have traveled when it hits the floor after the cord is cut? 3. OK, one more time. This time the magnet has mass 5.76 kg and the force pulling it to the right is 58.4 N. When the magnet hits the floor, it continues being pulled to the right by the same magnetic force as before. The coefficient of kinetic friction between the magnet and the…In this figure what magnitude force provides 9.0 N m net torque about the axel?3. Same situation as in the previous two problems this time the magnet s mass is 4.00 kg and the magnetic force pulling it to the right is 140.6 N. The length of the cord is 0.77 m, and the ceiling is 3.24 m above the floor. Suppose that you cut the cord and the magnet falls to the floor while still being pulled to the right by the force of 140.6 N. How long will it take the magnet to hit the floor? 1.258 s 0.157 s 0.786 s 0.314 s