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A small ball is rotating in a circular horizontal path. The ball is held by a rigid rod. The moment of inertia of the ball is 2.43 kg m and its angular rate of rotation is 4.00 rad/s. What is the kinetic energy of the ball in Joules? a. 21 b. 19.4 C. 4.9 d. 58.2 38 9

A small ball is rotating in a circular horizontal path. The ball is held by a rigid rod. The moment of inertia of the ball is 2.43 kg m and its angular rate of rotation is 4.00 rad/s. What is the kinetic energy of the ball in Joules? a. 21 b. 19.4 C. 4.9 d. 58.2 38 9

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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6 only I provided formulas sheet must use that plus can you explain me easy way step by step please
Circular motion: ac = Eet = ma; d. 0.05 R Weight: F- mg,; g- 9.8 m/s; Pevr = Δι e. 0.5 1 m v²; Potential energy: Kinetic energy: K = U, - mgy E = E E = U+K Rotational motion: e = 1 rev = 2n rad; v = o r; a = a r; v? a, = = o'r; o = 0o + at; e = 0o t + 20a = o - 0, K- lo ?. t-rx F; 7=rFsing; ET = Ia; 1 Idisk = mR2 1 Ipoint mass= mr2 IyF mR + out Rin ng horizontally in a ci 1 Ihoop = mR? Irod(center) = mL? Irod(end) = mL Iball = mR? Ishell = mR? 12 work: W=t 0; K=-lo 2 dW P=- dt I= Icom + MD² W Pav = At 1 m Vcom 2 2. Rolling: Vcom = Ro K= Io T=f,R F,max = H,Fn Incline: Fe mgsin0 Fg mgcos0 Angular momentum: Lpoint mass =m rxv L= mrvsin 0; L=m (r.Vy - ryV3)k L= Io mıy1+m2y2 m1 +m2 m,x1 +m2x2 LI = Lt I, oj =I 202 X com Y com = m +m2 A small ball is rotating in a circular horizontal path. The ball is held by a rigid rod. The moment of inertia of the ball is 2.43 kg m and its angular rate of rotation is 4.00 rad/s. What is the kinetic energy of the ball in Joules? ota 6. a. 21 b. 19.4 c. 4.9 d. 58.2 4. A ng e. 38.9 un 7. A small ball is rotating in a circular path on a massless, rigid wire about a vertical post. The mass of the ball is 6.0 kg and its distance from the stick is 1.2 m. What is the moment of tor of mass of the ball about the axis of rotation?
Transcribed Image Text:Circular motion: ac = Eet = ma; d. 0.05 R Weight: F- mg,; g- 9.8 m/s; Pevr = Δι e. 0.5 1 m v²; Potential energy: Kinetic energy: K = U, - mgy E = E E = U+K Rotational motion: e = 1 rev = 2n rad; v = o r; a = a r; v? a, = = o'r; o = 0o + at; e = 0o t + 20a = o - 0, K- lo ?. t-rx F; 7=rFsing; ET = Ia; 1 Idisk = mR2 1 Ipoint mass= mr2 IyF mR + out Rin ng horizontally in a ci 1 Ihoop = mR? Irod(center) = mL? Irod(end) = mL Iball = mR? Ishell = mR? 12 work: W=t 0; K=-lo 2 dW P=- dt I= Icom + MD² W Pav = At 1 m Vcom 2 2. Rolling: Vcom = Ro K= Io T=f,R F,max = H,Fn Incline: Fe mgsin0 Fg mgcos0 Angular momentum: Lpoint mass =m rxv L= mrvsin 0; L=m (r.Vy - ryV3)k L= Io mıy1+m2y2 m1 +m2 m,x1 +m2x2 LI = Lt I, oj =I 202 X com Y com = m +m2 A small ball is rotating in a circular horizontal path. The ball is held by a rigid rod. The moment of inertia of the ball is 2.43 kg m and its angular rate of rotation is 4.00 rad/s. What is the kinetic energy of the ball in Joules? ota 6. a. 21 b. 19.4 c. 4.9 d. 58.2 4. A ng e. 38.9 un 7. A small ball is rotating in a circular path on a massless, rigid wire about a vertical post. The mass of the ball is 6.0 kg and its distance from the stick is 1.2 m. What is the moment of tor of mass of the ball about the axis of rotation?
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