A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between the patients using and not using the new drug. Assume that the hours of sleep are normally distributed for the population of patients both before and after taking the new drug. Patient Hours of sleep without the drug Hours of sleep with the new drug 1 2 3 4 5 6 7 8 9 5.4 5.4 2.2 3.7 3.4 5.5 2.6 4.2 4.2 8.1 6.5 3.2 5.3 4.5 8 5.1 5.3 6.4 Step 3 of 4: Calculate the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Copy Data

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A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so,
the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are
listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between the patients using and not using the new drug.
Assume that the hours of sleep are normally distributed for the population of patients both before and after taking the new drug.
Patient
Hours of sleep without the drug
Hours of sleep with the new drug
2
12 3 4 5 6 7 8 9
5.4 5.4 2.2 3.7 3.4 5.5 2.6 4.2 4.2
8.1 6.5 3.2 5.3 4.5 8 5.1 5.3 6.4
Step 3 of 4: Calculate the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
Copy Data
Transcribed Image Text:A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between the patients using and not using the new drug. Assume that the hours of sleep are normally distributed for the population of patients both before and after taking the new drug. Patient Hours of sleep without the drug Hours of sleep with the new drug 2 12 3 4 5 6 7 8 9 5.4 5.4 2.2 3.7 3.4 5.5 2.6 4.2 4.2 8.1 6.5 3.2 5.3 4.5 8 5.1 5.3 6.4 Step 3 of 4: Calculate the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Copy Data
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