A skydiver jumps out of a helicopter at6000 feet above the ground. As hedescends, the force of air resistance actingupon him continually changes. The free-body diagrams below represent themagnitude and direction of the two forcesacting upon the skydiver at six positionsduring his fall.MC6000 feetCRCFguv3000 feet-900 Nm/s/sFair=1100 Ngrav=900 Nm/s/sa=5500 feetFair 200 NFay=900 N2900 feetm/s/s a=Faiz-1500 N900 N4500 feetFair= 900 Nv-900 N1500 feetm/s/sFair-900 Ngav 900 Nm/s/s a=For each diagram (altitude) apply Newton'ssecond law (Fnet = m*a) to determine theacceleration value. Be sure to note thedirection of acceleration as well. (Hint: Todetermine the sky diver's mass, considerwhat you have learned about the linkbetween gravitational force and mass.)m/s/sYou may use 10 m/s/s as an approximationfor g (gravitational acceleration).

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Description: A skydiver jumps out of a helicopter at6000 feet above the ground. As hedescends, the force of air resistance actingupon him continually changes. The free-body diagrams below represent themagnitude and direction of the two forcesacting upon the skyd

In the first diagram, Determine the net force. Since the skydiver experiences only the…

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A skydiver jumps out of a helicopter at 6000 feet above the ground. As he descends, the force of air resistance acting upon him continually changes. The free- body diagrams below represent the magnitude and direction of the two forces acting upon the skydiver at six positions during his fall. K 6000 feet (Sch C Fgrav-900 N 3000 feet m/s/s Fair 1100 N ga-900 N a= 5500 feet Fair 200 N gav 900 N 2900 feet m/s/s Fair-1500 N gav 900 N m/s/s 4500 feet Fair-900 N 1500 feet 900 N m/s/s Fair-900 N 900 N m/s/s m/s/s For each diagram (altitude) apply Newton's second law (Fnet = m*a) to determine the acceleration value. Be sure to note the direction of acceleration as well. (Hint: To determine the sky diver's mass, consider what you have learned about the link between gravitational force and mass.) You may use 10 m/s/s as an approximation for g (gravitational acceleration).

A skydiver jumps out of a helicopter at 6000 feet above the ground. As he descends, the force of air resistance acting upon him continually changes. The free- body diagrams below represent the magnitude and direction of the two forces acting upon the skydiver at six positions during his fall. K 6000 feet (Sch C Fgrav-900 N 3000 feet m/s/s Fair 1100 N ga-900 N a= 5500 feet Fair 200 N gav 900 N 2900 feet m/s/s Fair-1500 N gav 900 N m/s/s 4500 feet Fair-900 N 1500 feet 900 N m/s/s Fair-900 N 900 N m/s/s m/s/s For each diagram (altitude) apply Newton's second law (Fnet = m*a) to determine the acceleration value. Be sure to note the direction of acceleration as well. (Hint: To determine the sky diver's mass, consider what you have learned about the link between gravitational force and mass.) You may use 10 m/s/s as an approximation for g (gravitational acceleration).

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 95CP: On June 25, 1983, shot-putter Udo Beyer of East Germany threw the 7.26-kg shot 22.22 m, which at...

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