A sinusoidal wave traveling in the positive x direction and has an amplitude of 8 cm, a wavelength of 4cm cm, and a frequency of 20.0 Hz. The transverse position of an element of the medium at t = 0, x = 0 is y = 4 cm, and the element has a positive velocity here. The time expression of the wave is: A-y = 0. 08 sin ( 50πχ-40πt +-) | 5n) B- y = 0.08 sin (50nx – 40nt + ) C– y = 0. 08 sin(50nx + 40nt - D- y = 0.08 sin (50nx + 40nt + E- y = 0.08 sin (50nx + 40nt 3
A sinusoidal wave traveling in the positive x direction and has an amplitude of 8 cm, a wavelength of 4cm cm, and a frequency of 20.0 Hz. The transverse position of an element of the medium at t = 0, x = 0 is y = 4 cm, and the element has a positive velocity here. The time expression of the wave is: A-y = 0. 08 sin ( 50πχ-40πt +-) | 5n) B- y = 0.08 sin (50nx – 40nt + ) C– y = 0. 08 sin(50nx + 40nt - D- y = 0.08 sin (50nx + 40nt + E- y = 0.08 sin (50nx + 40nt 3
Related questions
Question
Transcribed Image Text:A sinusoidal wave traveling in the positive x direction and has an
amplitude of 8 cm, a wavelength of 4cm cm, and a frequency of 20.0
Hz. The transverse position of an element of the medium at t = 0, x = 0
is y = 4 cm, and the element has a positive velocity here. The time
expression of the wave is:
A- y = 0.08 sin (50nx – 40nt + -)
B- y = 0.08 sin (50nx
5n
- 40nt +
C – y = 0.08 sin(50nx + 40nt
D- y = 0.08 sin (50nx + 40nt +
6
5n
E- y = 0.08 sin ( 50nx + 40nt
A
В
C
O E
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
