A single effect evaporator was used to concentrate 8000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 25 ° C. The evaporator is operated on Steam (85% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it (a) Steam demand rate = Answer kg / hour. b. Steam economy when condensate temperature is released at

A single effect evaporator was used to concentrate 8000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 25 ° C. The evaporator is operated on Steam (85% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it (a) Steam demand rate = Answer kg / hour. b. Steam economy when condensate temperature is released at

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter40: Typical Operating Conditions

Section: Chapter Questions

Problem 9RQ: The evaporator design temperature may in some cases operate at a slightly ____(higher or lower)...

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Indonesia Inggris A single effect evaporator was used to concentrate 8000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 25 ° C. The evaporator is operated on Steam (85% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it (a) The rate of demand for steam? b. Steam economy if condensate temperature is released at 75 ° C.?
A single effect evaporator was used to concentrate 8000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 15 ° C. The evaporator is operated on Steam (85% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 80 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it (a) Steam demand rate = Answerkg / hour. b. Steam economy when condensate temperature is released at 75 ° C. = Answer(kg of water evaporated / kg of steam)
A single effect evaporator was used to concentrate 8000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 25 ° C. The evaporator is operated on Steam (80% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it a. Steam demand rate = ....... kg / hour. b. Steam economy when condensate temperature is released at 75 ° C. = ....... (kg of water evaporated / kg of steam)
A single effect evaporator was used to concentrate 10000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 25 ° C. The evaporator is operated on Steam (85% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). a. Steam demand rate = kg / hour. b. Steam economy when condensate temperature is released at 75 ° C. = (kg of water evaporated / kg of steam)
A single-effect evaporator concentrates 4.00 kg/s of a 10% by mass solution of H2SO4. The entering feed is at 25 °C. The vapor released at the top has a mass flow rate of 3.20 kg/s. The evaporator operates at a total pressure of 30.2 kPa at 90 °C. What is the rate of heat transfer in the evaporator? Use a steam table for the enthalpy of the vapor?
回MO zain IQ Asiacell The thermodynamic properties of refrigerant R22 mixture of liquid and vapor leaving the expansion device and entering the evaporator are; pressure of 498 kPa, temperature of O °C, fraction dryness (x) of 0.238, saturated liquid enthalpy of 200 kJ/kg, and saturated vapour enthalpy of 405 kJ/kg. The pressure of this refrigerant at the entrance of the condenser is measured to be 19.3 bar. After the subcooling process, the enthalpy in (kJ/kg) and the pressure in (MPa) of this refrigerant have been measured and were found to be 199.47 kJ/kg and 2.3 MPa none of these answers. 199.47 J/kg and 2.3 Pa 239. 68 kJ/kg and 1.96 MPa 248.79 J/kg and 1.93 Pa 248.79 kJ/kg and 1.93 MPa
Liquid ammonia at 30°C is metered through an expansion valve to an evaporator operating at a saturation temperature of -5°C. Calculate the dryness fraction of the refrigerant entering the evaporator. 21.7% 0.1288% 12.88% 15.78%
2. Double-Effect Evaporator with Reverse Feed. A feed rate of 20410 kg/hr of 10 wt % NaOH solution at 48.9 °C is being concentrated in a double-effect reverse-feed evaporator to produce a 50% solution. Saturated steam at 178.3 °C is fed to the first evaporator and the pressure in the second effect is 10.34 kPa abs. The heat-transfer coefficient for each effect is assumed to be 2840 W/m?-K. Calculate the heat-transfer area, the steam consumption rate, and the steam economy.
In a refrigerating plant using R12 the vapour leaves the evaporator dry saturated at 1,826 bar and is compressed to 7,449 bar. The temperature of the vapour leaving the compressor is 45 degrees Celsius and is throttled to the evaporator pressure. 1.Complete the table below 2.Calculate the specific enthalpy at the compressor exit to 2 decimal places. 3.Calculate the mass flow rate of refrigerant in kg/s 4.Find the power requirement in KW to 3 decimal places and also find the coefficient of performance to 1 decimal place
On a hot summer day, the temperature is 35 ° C, barometric pressure 103 kPa and relative humidity 90%. One The air conditioner draws the outside air and cools it to 20 ° C and raises the air to 12500 L / h. Calculate the condensation rate of the moisture (kg / h) and the flow rate of the air drawn from the outside.
The pressure at which the steam should be reheated.Notes: Assume the steam is reheated to the inlet temperature of the high-pressure turbine. The moisture content of the steam at the exit of the low-pressure turbine is not to exceed 9.5%
HUMIDIFIER: MASS BALANCE On a hot summer day, the air is at 30.6 ° C and 80% relative humidity. The air conditioning in a building supplies 30 m3 / min of air at 13 ° C to keep the air inside the building at an average temperature of 24 ° C and 40% relative humidity. If the ventilation switch of the air conditioner is “open”, the air from outside enters the unit as shown in the drawing (I): The air conditioner cools the air to a temperature low enough to condense the required amount of water and reheat it to 13 ° C (unsaturated current), at which point it has the same absolute humidity as the air in the building. Calculate: a. the speed at which condenses water (kg / min) b. the temperature at which the air must be cooled to condense water at this rate. Do the calculations without using the psychrometric chart (although 1 atm of current pressure can be assumed). If the ventilation switch is closed, as normal, the air from inside the building would be recirculated in the air…