A simple U tube manometer is used to measure the pressure of oil flowing in a pipeline. Its left limb is open to the atmosphere and the right limb is connected to the pipe. The center of the pipe is 166 mm below the level of mercury in the left limb. If the difference of mercury level in the two limbs is 259 mm, determine the gauge pressure of the oil in the pipe in Pascal. The specific gravity of the oil & mercury is 1.86 and 13.6 respectively. Solution: (i) Density of oil in kg/m³ (ii) Density of mercury in kg/m³ (iii) Height of the Oil in the right limb (in meters of oil) h₁ (iv) The gauge pressure of the oil in the pipe in (in Pascal)

The manometer pressure at pipe A is about 30mmHg and the initial differential reading of Mercury is 0.30 m as shown.Calculate the absolute pressure at pipe B.

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The device shown is the buoyancy measurement device used to measure the liquid height change. A pressure sensor is installed at the bottom of the tank, and a force sensor is installed to measure the upward force on the horizontal lever. The distances to the pivot point from the force sensor and cylinder are X1 and X2, respectively.  The reference pressure at the reference liquid height, h0, to the bottom of the cylinder is pref. (4) If the force measured by the force sensor is Fsensor = 7.53 N, X1 = 1.58 m, X2 = 0.17 m, the diameter of the cylinder is D = 0.05 m,  and the specific weight of the liquid is γf = 8.70 kN/m3, calculate the liquid height difference, Δh, relative to the reference height h0. __________ m.