A simple random sample of sizen is drawn from a population that is normally distributed. The sample mean, x, is found to be 110, and the sample standard deviation s, is found to be 10. (a) Construct an 80% confidence interval about u if the sample size, n, is 15. (b) Construct an 80% confidence interval about u if the sample size, n, is 28. (c) Construct a 90% confidence interval about u if the sample size, n, is 15. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct an 80% confidence interval about u if the sample size, n, is 15. Lower bound: 106.5 ; Upper bound: 113.5 (Use ascending order. Round to one decimal place as needed.) (b) Construct an 80% confidence interval about u if the sample size, n, is 28. Lower bound: ; Upper bound: (Use ascending order. Round to one decimal place as needed.)

I neeed help with answering quesition 8 part a and b

What about parts c and d?

Need solution for D, E and F please

Could you provide more detailed proof for each part?

=4 Side a = 23 12 apis 401 = 2 bur // 1² 0

Simplify. 3x 1 1 -2y 2 9x-2 - 4y 3x-1- 2y-1 9x-2 - 4y - 2 II

Rachael has 20 thin rods whose lengths, in centimetres, are 1,2,3,…,201,2,3,…,20. Any two rods can be connected at their ends. Rachael selects three rods to make a triangle, then three other rods to make a second triangle, and so on. only one of rachel's rods cannot be the side of a triangle. determine which one.

answer b and c ...

The first angle of a triangle is four times the third angle; the second angle is twenty degrees less than three times the third angle. Let the measure of the third angle be C.