A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 110, and the sample standard deviation, s, is found to be 10. (a) Construct an 80% confidence interval about µ if the sample size, n, is 15. (b) Construct an 80% confidence interval about u if the sample size, n, is 28. (c) Construct a 90% confidence interval about u if the sample size, n, is 15. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? E Click the icon to view the table of areas under the t-distribution. (a) Construct an 80% confidence interval about u if the sample size, n, is 15. Lower bound: ; Upper bound: (Use ascending order. Round to one decimal place as needed.)

The law of large numbers states that as the number of observations drawn at random from a population with finite mean  increases, the mean  of the observed values:   a. tends to get closer and closer to the population mean .   b. gets smaller and smaller.   c. gets larger and larger.   d. fluctuates steadily between 1 standard deviation above and 1 standard deviation below the mean.   I collect a random sample of size n from a population and compute a 95% confidence interval for the proportion I observe from the population. What could I do to produce a new confidence interval with a larger width (larger margin of error) based on these same data?   a. I could use the same confidence level but compute the interval n times; approximately 5% of these intervals will be larger.   b. Nothing can guarantee absolutely that I will get a larger interval; I can only say the chance of obtaining a larger interval is 0.05.   c. I could use a smaller confidence…

Determine the t-score for a 95% confidence interval for a population mean from a sample of size 6. t =     [three decimal accuracy]

A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean, x​, is found to be 115​, and the sample standard​ deviation, s, is found to be 10. ​(a) Construct an 80​% confidence interval about μ if the sample​ size, n, is 25. ​(b) Construct an 80​% confidence interval about μ if the sample​ size, n, is 12. ​(c) Construct a 70​% confidence interval about μ if the sample​ size, n, is 25. ​(d) Could we have computed the confidence intervals in parts​ (a)-(c) if the population had not been normally​ distributed?

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. (b) Construct a 98% confidence interval about µ if the sample size, n, is 12. (c) Construct a 70% confidence interval about u if the sample size, n, is 16. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. Lower bound:; Upper bound: (Use ascending order. Round to one decimal place as needed.)

A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean,x​, is found to be 112​, and the sample standard​ deviation, s, is found to be 10. A. Construct a 98​% confidence interval about μ if the sample​ size, n, is 18. Lower bound-  Upper Bound-  B. Construct a 98​% confidence interval about μ if the sample​ size, n, is 28. Lower bound-  Upper Bound- C. Construct a 99​% confidence interval about μ if the sample​ size, n, is 18. Lower bound-  Upper Bound-

A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean, x​, is found to be 110​, and the sample standard​ deviation, s, is found to be 10. ​(a) Construct a 98​% confidence interval about μ if the sample​ size, n, is 15. ​(b) Construct a 98​% confidence interval about μ if the sample​ size, n, is 24. ​(c) Construct a 99​% confidence interval about μ if the sample​ size, n, is 15. ​(d) Could we have computed the confidence intervals in parts​ (a)-(c) if the population had not been normally​ distributed?

A simple random sample with n = 52 provided a sample mean of 24.0 and a sample standard deviation of 4.6. a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c. Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased? V - Select your answer - They increase They decrease They stay the same It cannot be determined from the given data The margin of error increases and the confidence interval becomes narrower The margin of error decreases and the confidence interval becomes wider

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 104, and the sample standard deviation, s, is found to be 8. (a) Construct a 95% confidence interval about u if the sample size, n, is 22. (b) Construct a 95% confidence interval about u if the sample size, n, is 16. (c) Construct a 90% confidence interval about u if the sample size, n, is 22. (d) Should the confidence intervals in parts (a)-(c) have been computed if the population had not been normally distributed? (a) Construct a 95% confidence interval about u if the sample size, n, is 22. Lower bound: 100.5; Upper bound: 107.5 (Round to one decimal place as needed.) (b) Construct a 95% confidence interval about u if the sample size, n, is 16. Lower bound: Upper bound: (Round to one decimal place as needed.)