A simple random sample of size n = 20 is drawn from a population that is normally distributed. The sample mean is found to be x = 60 and the sample standard deviation is found to be s = 19. Construct a 95% confidence interval about the population mean. The lower bound is The upper bound is (Round to two decimal places as needed.)

A simple random sample of size n= 12 is drawn from a population that is normally distributed. The sample mean is found to be x= 63 and the sample standard deviation is found to be s = 13. Construct a 95% confidence interval about the population mean. The lower bound is The upper bound is (Round to two decimal places as needed.)

Body Mass Index: In a survey of adults with diabetes, the average body mass index (BMI) in a sample of 1928 women was 31.30 with a standard deviation of 0.3. The BMI in a sample of 1559 men was 30.50, with a standard deviation of 0.6. Part 1 of 2 (a) Construct a 99% confidence interval for the difference in the mean BMI between women and men with diabetes. Let H, denote the mean BMI for women with diabetes. Use the TI-84 calculator and round the answers to two decimal places. A 99% confidence interval for the difference in the mean BMI between women and men with diabetes is Part: 1 / 2 Part 2 of 2 (b) Does the confidence interval contradict the claim that the mean BMI is the same for both men and women with diabetes? The confidence interval (Choose one) this claim.

The mean tar content of a simple random sample of 25 unfiltered king-size cigarettes is 21.4 mg, with a standard deviation of 3 mg. The mean tar content of a simple random sample of 25 filtered 100-mm cigarettes is 13.0 mg with a standard deviation of 3.8 mg. The accompanying table shows the data. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Let population 1 be unfiltered king-size cigarettes. Complete parts (a) through (c) below. Click the icon to view the data. a. Use a 0.05 significance level to test the claim that unfiltered king-size cigarettes have a mean tar content greater than that of filtered 100-mm cigarettes. What does the result suggest about the effectiveness of cigarette filters? Identify the null and alternative hypotheses. O B. Ho: H1 =H2 O C. Ho: H1 #H2 H1: H1 =H2 O A. Ho: H1 = H2 H:H1 H2 O F. Ho: H1 = H2 H1:H1> H2 H:H1=H2 Hq: H1…

A random sample of 15 exam scores showed a standard deviation of 6.0 points. Find the 95 percent confidence interval for the population standard deviation. Use Appendix E to obtain the values of  χ2LχL2 and χ2UχU2 . (Round your answers to 2 decimal places.) The 95% confidence interval is from ______ to __________  .

A simple random sample of size n=17 is drawn from a population that is normally distributed. The sample mean is found to be x= 69 and the sample standard deviation is found to be s= 20. Construct a 95% confidence interval about the population mean. ..... The lower bound is The upper bound is

Use technology to construct the confidence intervals for the population variance o and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.90, s = 5.76, n = 26 The confidence interval for the population variance is ( ). (Round to two decimal places as needed.) The confidence interval for the population standard deviation is ( ). (Round to two decimal places as needed.)

A population has a mean of 300 and a standard deviation of 40. Suppose a simple random sample of size 100 is selected and x¯ is used to estimate μ .What is the probability that the sample mean will be within +/- 5 of the population mean?

A simple random sample of size n=51 is taken from a normally distributed original population. The sample standard deviation is s=27. Find the 95% confidence interval for the population standard deviation O.

The z confidence interval for the mean of a Normal population will have a specified margin of error m when the sample size is: a. n = (=*o/m). b. n = (z/m)². O c. n = (*o/m)². d. n ==*o/m.