A simple random sample from a population with a normal distribution of 100 body temperatures has x = 98.90°F and s = 0.63°F. Construct a 90% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. F

In a sample of 12 randomly selected high school​ seniors, the mean score on a standardized test was 1182 and the standard deviation was 161.6.Further research suggests that the population mean score on this test for high school seniors is 1012. Does the​ t-value for the original sample fall between −t0.95 and t0.95​? Assume that the population of test scores for high school seniors is normally distributed.   What is The​ t-value?   And does or does not it not  fall between −t0.95 and t0.95 because t0.95=? ​(Round to two decimal places as​ needed.)

The mean pulse rate (beats per minute) of a random sample of 40 males was 67.3 bpm. For a random sampl of 40 females the mean was 77.5 bpm. The population standard deviation for males is 10.3 bpm and 11.6 bpm for females. Using the P-Value method and test the claim that there is a difference in mean pulse rates. Use alpha = 0.03. Step 5: There is enough evidence to reject the claim that there is a difference in pulse rates for males and females. O There is enough evidence to support the claim that there is a difference in pulse rates for males and females. There is not enough evidence to reject the claim that there is a difference in pulse rates for males and females. There is not enough evidence to support the claim that there is a difference in pulse rates for males and females. SAMSUNG 女 & 4 5 7 8 r t y %24

Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches.  A particular man is 80 inches tall.  Find the z-score of his height.  (Round to two decimal places.)

GPAS at CCSU are normally distributed with a mean of 2.14 and a standard deviation of 0.52. Find the z-score for a GPA of 2.78.

Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3  minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40  individuals. The average time that the 40  people spent reading the paper was 12.4  minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90%  confidence interval of the mean. (a) State the hypothesis and identify the claim with the correct hypothesis. :H0     ▼(Choose one)   :H1     ▼(Choose one)   This hypothesis test is a ▼(Choose one) test.       (b)Find the critical value(s). Round the answer to 2  decimal places, if necessary.   Critical values:   (c)Compute the test value. Round the answer to at least 2 decimal places, if necessary. z=   (d)Make the decision.…

GPAs at CCSU are normally distributed with a mean of 2.25 and a standard deviation of 0.45. Find the z-score for a GPA of 2.49.

Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3  minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40  individuals. The average time that the 40  people spent reading the paper was 12.4  minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90%  confidence interval of the mean. **NOTE** I already have answer for a,b, and c    (d)Make the decision.   ▼(Choose one) the null hypothesis.       (e)Summarize the results.   There ▼(Choose one) enough evidence to support the claim that there is a change in the average time an individual spends reading the newspaper. Find the 90% confidence interval of the mean. Round the answers to nearest whole number. <u<   (f)Do the results agree?…