A simple plate capacitor can store 7.0 x 10-5 C at a potential of 12,000 V. If a BatiO3 dielectric material with r= 2100 is used between the plates, which have an area of 5.0 x 10-5 m2, what must be the separation distance between the plates? For using the maximum capacitance requirement of ~ 7 x 10-9 C, what would be the distance between both the plates? Is it feasible for fabricating such capacitor? [Consider rest of the parameters like capacitor area, r, potential etc., are constant]

A parallel-plate capacitor has circular plates of 10.8 cm radius and 1.23 mm separation. (a) Calculate the capacitance. (b) What charge will appear on the plates if a potential difference of 125 V is applied? (a) Number i (b) Number i Units Units

(a) When a 5.00-V battery is connected to the plates of a capacitor, it stores a charge of 28.0 µč. What is the value of the capacitance? µF (b) If the same capacitor is connected to a 20.0-V battery, what charge is stored? µC e Show My Work (Optional)

MY YSY When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew µF %3D (b) What is the new potential difference between two plates? Vnew volts (c) Find the energy stored in the new capacitor. Unew %3D

Question no.3: A parallel-plate capacitor has plates of area 0.12 m2and a separation of 1.2 cm. A battery charges the plates to a potential dif-ference of 120 V and is then disconnected. A dielectric slab of thick-ness 4.0 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab?

A certain capacitor has a capacitance of 4μF when its plates are separated by 0.2 mm of vacant space. A battery is used to charge the plate to a potential difference of 500 V and is then disconnected from the system. (a) What will be the potential difference across the plates if a sheet of mica 0.2 mm thick is inserted between the plates? (b) What will the capacitance be after the dielectric is inserted? (c) What is the permittivity of mica?