A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2.max = 9h,max and T2 = 3T, h2.max = 4h1,max and T2 = T, %3D %3D %3D Then we have: Then we have: h2max = 4h,max and T,= 27, h2max hmax/2 and T, T,

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ogle.com/forms/d/e/1FAlpQLSfbUydyGoVwp0YIVGZZIkhjNP2IMSDTnS7Kgtpy4X8Rol8_fg/formResponse
A simple pendulum is set into motion at two different times with different initial
conditions. The first time: the bob is in its equilibrium position and is given an
initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the
period of motion is T1. The second time: the bob is in its equilibrium position and
is given an initial velocity +6 m/s. The maximum height reached by the bob is
h2,max and the period of motion is T2. Assume that the motion is simple
harmonic, which of the following is true?
h2.max
9hmax and T,
3T,
h2.max = 4h, max and T, = T,
Then we have:
Then we have:
= 4h, max and T, 27,
hz.max=h1.max/2 and T, T,
h2.max
Transcribed Image Text:ogle.com/forms/d/e/1FAlpQLSfbUydyGoVwp0YIVGZZIkhjNP2IMSDTnS7Kgtpy4X8Rol8_fg/formResponse A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +6 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2.max 9hmax and T, 3T, h2.max = 4h, max and T, = T, Then we have: Then we have: = 4h, max and T, 27, hz.max=h1.max/2 and T, T, h2.max
A Phys220 Spring-2021_exam-1
E PHYS220 Spring-2021 Exam-1
A docs.google.com/forms/d/e/1FAlpQLSfbUydyGoVwp0YIVGZZIkhjNP2IMSDīnS7Kgtpy4X8Rol8_fg/formResponse
A traveling wave on a taut string with a tension force T, is given by the wave
function: y(x,t) = 0.05sin(TX-100rtt), wherex and y are in meters and t is in
seconds. If the linear mass density of the string is given by µ = 0.01 kg/m, then
the tension force on the string is,
0.5 N
100 N
O 1N
O 25 N
10 N
A mass-spring system oscillates on a frictionless horizontal surface in simple
harmonic motion with an amplitude A = 0.16 m. At what position (x = ?) would the
kinetic energy of the system be equal to three times its elastic potential energy
(K = 3U)?
O At x = ±0 1m
O At x = #0 05 m
O At x= 10.04 m
O At x = ±0 08 m
4:41
4/12/2
Transcribed Image Text:A Phys220 Spring-2021_exam-1 E PHYS220 Spring-2021 Exam-1 A docs.google.com/forms/d/e/1FAlpQLSfbUydyGoVwp0YIVGZZIkhjNP2IMSDīnS7Kgtpy4X8Rol8_fg/formResponse A traveling wave on a taut string with a tension force T, is given by the wave function: y(x,t) = 0.05sin(TX-100rtt), wherex and y are in meters and t is in seconds. If the linear mass density of the string is given by µ = 0.01 kg/m, then the tension force on the string is, 0.5 N 100 N O 1N O 25 N 10 N A mass-spring system oscillates on a frictionless horizontal surface in simple harmonic motion with an amplitude A = 0.16 m. At what position (x = ?) would the kinetic energy of the system be equal to three times its elastic potential energy (K = 3U)? O At x = ±0 1m O At x = #0 05 m O At x= 10.04 m O At x = ±0 08 m 4:41 4/12/2
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