A simple curve connects two tangents AB and BC with bearings N 85°30'00" E and S 68°30'00"E, respectively. If the stationing of B is 4+360.2, and the stationing of PC is 4+288.4,determine the following:a. RadiusAnswer: R= [radius] mb. External DistanceAnswer: E= [external] mc. Middle OrdinateAnswer: M= [middle] md. Chord DistanceAnswer: Lc= [chord] me. Length of CurveAnswer: L= [curve] m27

"Since you have posted a question with multiple sub-parts, we will solve first three sub- parts for…

A simple curve connects two tangents AB and BC with bearings N 85°30'00" E and S 68°30'00"E, respectively. If the stationing of B is 4+360.2, and the station X determine the following: a. Radius Answer: R= [radius] m b. External Distance Answer: E= [external] m c. Middle Ordinate Answer: M= [middle] m d. Chord Distance Answer: Lc= [chord] m e. Length of Curve Answer. L= [curve] m ▷

A simple curve connects two tangents AB and BC with bearings N 85°30'00" E and S 68°30'00"E, respectively. If the stationing of B is 4+360.2, and the station X determine the following: a. Radius Answer: R= [radius] m b. External Distance Answer: E= [external] m c. Middle Ordinate Answer: M= [middle] m d. Chord Distance Answer: Lc= [chord] m e. Length of Curve Answer. L= [curve] m ▷

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please show all work clear
1. 1. A simple curve connects two tangents AB and BC with bearings N 85 deg 30' E and S68deg 30' E respectively. If the stationing of the vertex is 4+360.2 and the stationing of PC is 4+288.40. a. Determine the radius. b. Determine the external distance c. Determine the middle ordinate. d. Determine the chord distance e. Determine the length of the curve.
I need the answer as soon as possible
Find the radius of curvature of the following curves at the point indicated. T= tan 6 at 0 %3D
For a highway curve with R = 1000 m, I = 16°30', and Pl station = 3 +264.759 m, calculate the requested values to lay out the circular curve at full stations (30 m). Part A Calculate the degree of curvature. Express your answer in degrees to five decimal places. Da = Submit Part B L= Submit Part C VE ΑΣΦ Calculate the circular curve length. Express your answer to three decimal places and include appropriate units. Request Answer T = ΠΑ Value Request Answer ↓↑ vec ΠΑ Value Units Calculate the tangent distance. Express your answer to three decimal places and include appropriate units. ? Units ? ?
please show the detailed solution. thank you so much!
Determine the resulting surface area when the curve y = a15 is rotated about the y-axis in the interval 0 < « < 12. 3712 15 O 671.5 3812 17 O 3612 12
Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' %3D R1 = 250 m. T1 = 215 m. Sta PI = 1 +376.50 Find I, R2, and T2 and stationing of the PC, PCC, and PT. ANSWERS: | = 91° 20' R2 = 150.33 m. T2 = 174.46 m. LC = 163.62 m. LC2 = 141.24 m.
A simple curve connects two tangents AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E respectively. If the stationing of the Vertex is 6+029.21 and the stationing of PC is 5+957.41: 16.1. Determine the radius in meters. 16.2. Determine the external distance in meters. 16.3. Determine the middle ordinate in meters. (CONSIDER 2-DECIMAL PLACES)
Given the following elements of a circular curve: middle ordinate = 2 m; length of long chord = 70 m. Find its degree of curve, use arc basis.
S Curves V Problem: 1+12 For the given compound curve (see figure): a. Determine R, and R2. b. Determine T, and T2. c. Determine C, and C2. V d. Determine L, and L2. e. If the stationing of PC is at 10 + 304.62 m, determine the stationing of PCC and PT. T, +T2 РСС 12 = 15° PI, I = 12° Pl2 T1 T2 Y C1 PCO (Sta PC = 10 +304.62) PT Long chord 300m 12 = 15° R2 R, 02 I = 12°
The long chord from the point of curvature to the point of tangency of a compound curve is 549 5 meters face long and the angle it makes with the longer and shorter tangents are 17 degrees and 27 degrees respectively. The station of Pl is 10+180. Solve for the curved measurement from PC to PT in meters. solution pls asap