Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Concept explainers

Buckling of columns
The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.
Question

please help explain how to solve and include FBD

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A. F₂ F₁ B S 0 FL S E PAB = number (rtol=0.01, atol=1e-05) kip ? PAF = number (rtol=0.01, atol=1e-05) kip ? . PBC = number (rtol=0.01, atol=1e-05) kip ? PBF = number (rtol=0.01, atol=1e-05) kip PCD = number (rtol=0.01, atol=1e-05) kip ? PCF = number (rtol=0.01, atol=1e-05) kip ? PDE = number (rtol=0.01, atol=1e-05) kip ? PDF = number (rtol=0.01, atol=1e-05) kip PEF= number (rtol=0.01, atol=1e-05) kip h h
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Transcribed Image Text:A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A. F₂ F₁ B S 0 FL S E PAB = number (rtol=0.01, atol=1e-05) kip ? PAF = number (rtol=0.01, atol=1e-05) kip ? . PBC = number (rtol=0.01, atol=1e-05) kip ? PBF = number (rtol=0.01, atol=1e-05) kip PCD = number (rtol=0.01, atol=1e-05) kip ? PCF = number (rtol=0.01, atol=1e-05) kip ? PDE = number (rtol=0.01, atol=1e-05) kip ? PDF = number (rtol=0.01, atol=1e-05) kip PEF= number (rtol=0.01, atol=1e-05) kip h h
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Step 3: Force calculation in members
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Step 4: Force calculation in members
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Step 5: Force calculation in members
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