A satellite fires a thruster for 2 seconds to increase its speed by 3.0 m/s. If the satellite is 28 kg in mass, then how much average force does the thruster exert on the satellite? Ignore gravity and loss of mass due to thruster firing. There is no air drag in outer space. Hint: use impulse and the change of momentum.

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**Physics Problem: Calculating Average Force on a Satellite**

---

**Problem Statement:**

A satellite fires a thruster for 2 seconds to increase its speed by 3.0 m/s. If the satellite is 28 kg in mass, then how much average force does the thruster exert on the satellite?

**Conditions:**

- Ignore gravity and loss of mass due to thruster firing.
- There is no air drag in outer space.

**Hint:**

Use impulse and the change of momentum to solve this problem.

---

**Solution Approach:**

To solve this problem, we can use the concept of impulse which relates force, time, and change in momentum.

1. **Impulse-Momentum Theorem:**

   According to the impulse-momentum theorem:

   \[
   \text{Impulse} = \Delta p = F_{\text{average}} \times \Delta t
   \]

   where \(\Delta p\) is the change in momentum, \(F_{\text{average}}\) is the average force, and \(\Delta t\) is the time duration.

2. **Calculate Change in Momentum:**

   \[
   \Delta p = m \times \Delta v
   \]

   Given:
   - \(m = 28 \text{ kg}\)
   - \(\Delta v = 3.0 \text{ m/s}\)

   Therefore:

   \[
   \Delta p = 28 \text{ kg} \times 3.0 \text{ m/s} = 84 \text{ kg·m/s}
   \]

3. **Calculate Average Force:**

   Using the impulse equation:

   \[
   84 \text{ kg·m/s} = F_{\text{average}} \times 2 \text{ s}
   \]

   Solving for \(F_{\text{average}}\):

   \[
   F_{\text{average}} = \frac{84 \text{ kg·m/s}}{2 \text{ s}} = 42 \text{ N}
   \]

Therefore, the average force exerted by the thruster on the satellite is \(\boxed{42 \text{ N}}\).
Transcribed Image Text:**Physics Problem: Calculating Average Force on a Satellite** --- **Problem Statement:** A satellite fires a thruster for 2 seconds to increase its speed by 3.0 m/s. If the satellite is 28 kg in mass, then how much average force does the thruster exert on the satellite? **Conditions:** - Ignore gravity and loss of mass due to thruster firing. - There is no air drag in outer space. **Hint:** Use impulse and the change of momentum to solve this problem. --- **Solution Approach:** To solve this problem, we can use the concept of impulse which relates force, time, and change in momentum. 1. **Impulse-Momentum Theorem:** According to the impulse-momentum theorem: \[ \text{Impulse} = \Delta p = F_{\text{average}} \times \Delta t \] where \(\Delta p\) is the change in momentum, \(F_{\text{average}}\) is the average force, and \(\Delta t\) is the time duration. 2. **Calculate Change in Momentum:** \[ \Delta p = m \times \Delta v \] Given: - \(m = 28 \text{ kg}\) - \(\Delta v = 3.0 \text{ m/s}\) Therefore: \[ \Delta p = 28 \text{ kg} \times 3.0 \text{ m/s} = 84 \text{ kg·m/s} \] 3. **Calculate Average Force:** Using the impulse equation: \[ 84 \text{ kg·m/s} = F_{\text{average}} \times 2 \text{ s} \] Solving for \(F_{\text{average}}\): \[ F_{\text{average}} = \frac{84 \text{ kg·m/s}}{2 \text{ s}} = 42 \text{ N} \] Therefore, the average force exerted by the thruster on the satellite is \(\boxed{42 \text{ N}}\).
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