A sample of size n-92 is drawn from a normal population whose standard deviation is a 6.8. The sample mean is x -40.49.Part 1 of 2(a) Construct a 99.5% confidence interval for μ. Round the answer to at least two decimal places.A 99.5% confidence interval for the mean is<<Part 2 of 21(b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain.be valid since the sample size (Choose one) ▼large.The confidence interval constructed in part (a) (Choose one)X

Given that mean =40.49 , s.d = 6.8,n =92 ,alpha =0.005

Answered: A sample of size n-92 is drawn from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 24 items is drawn from a population whose standard deviation is unknown. The sample mean is x¯x¯ = 870 and the sample standard deviation is s = 25. Use Appendix D to find the values of Student’s t. (a) Construct an interval estimate of μ with 98% confidence. (Round your answers to 3 decimal places.) The 98% confidence interval is from blank to blank? (b) Construct an interval estimate of μ with 98% confidence, assuming that s = 50. (Round your answers to 3 decimal places.) The 98% confidence interval is from blank to blank? (c) Construct an interval estimate of μ with 98% confidence, assuming that s = 100. (Round your answers to 3 decimal places.) The 98% confidence interval is from blank to blank?
A research scholar wants to know how many times per hour a certain strand of virus reproduces. He wants to construct the 80% confidence interval with a maximum error of 0.2 reproductions per hour. Assuming that the mean is 6.4 reproductions and the variance is known to be 5.29, what is the minimum sample size required for the estimate? Round your answer up to the next integer.
Drill lifetime: A sample of 50 drills had a mean lifetime of 12.05 holes drilled when drilling a low-carbon steel. Assume the population standard deviation is 6.56. Part 1 of 3 (a) Construct a 95% confidence interval for the mean lifetime of this type of drill. Use tables or technology. Round your answers to at least two decimal places. OD- The confidence interval is Part 2 of 3 (b) The manufacturer of the drills claims that the mean lifetime is greater than 13. Does this confidence interval contradict this claim? (Choose one) ▼ the confidence interval (Choose one) v values greater than 13, so the claim (Choose one) V contradicted.
Age x and resting heart rate y were sampled for 25 randomly selected children from age 2 to 9. Summary information is: n = 25, Σx = 140.5, Σx2 = 903.75, Σy = 2567, Σy2 = 264, 457, Σxy = 14, 171.5 (a) Compute a 95% confidence interval for the average resting heart rate of 3 six year old children.
A sample of size n=77 is drawn from a population whose standard deviation is 0= 33. Part 1 of 2 (a) Find the margin of error for a 95% confidence interval for µ. Round the answer to at least three decimal places. The margin of error for a 95% confidence interval for µ is Part 2 of 2 (b) If the confidence level were 90%, would the margin of error be larger or smaller? (Choose one) ▼ because the confidence level is (Choose one) ▼
Energy drinks: A survey of college students reported that in a sample of 402 male college students, the average number of energy drinks consumed per month was 2.41 with a standard deviation of 3.18, and in a sample of 390 female college students, the average was 1.50 with a standard deviation of 4.77. Part: 0/2 Part 1 of 2 Construct a 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed. Let μ, denote the mean number of energy drinks consumed by men. Use tables to find the critical value and round the answers to at least two decimal places. A 80% confidence interval for the difference between men and women in the mean number of energy drinks consumed is 0<44-₂2 <0. X S Part: 1/2 Part 2 of 2 Based on the confidence interval, is it reasonable to believe that the mean number of energy drinks consumed may be the same for both male and female college students? It (Choose one) reasonable to believe that the mean number of energy drinks…
EStimation and Hypothesis Testing 3. A random sample of 17 wolf litters in Ontario, Canada, gave an average of x1 = 4.9 wolf pups per litter, with estimated sample standard deviation s = 1.0. Another random sample of 6 wolf litters in Finland gave an average of x2 * litter, with sample standard deviation s2 = 1.2. = 2.8 wolf pups per a. Find an 85% confidence interval for u, - U2, the difference in population mean litter size between Ontario and Finland b. Examine the confidence interval and explain what it means in the context of the problem. Does the interval consist of numbers that are all positive, all negative, or different signs? At the 85% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland?
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A sample of size n-92 is drawn from a normal population whose standard deviation is a-6.8. The sample mean is -40.49. Part 1 of 2 (a) Construct a 99.5% confidence interval for μ. Round the answer to at least two decimal places. A 99.5% confidence interval for the mean is