A sample of size 25 was taken from a very large population. Sample statistics, a and s, were used to find that the 80% confidence interval was (159.046, 166.954). S =

Q: If n = 20, a = 48, and s = 8, construct a confidence interval %3D at a 80% confidence level. Assume…

A:

Q: A sample of 28 was taken from a population, and r = .45. What is the 95% confidence interval for the…

A: Correlation coefficient: Correlation analysis is used to measure strength of the association between…

Q: If n=32, ¯xx¯(x-bar)=31, and s=14, construct a confidence interval at a 95% confidence level. Assume…

A: Given: x¯=31n=32s=1495% confidence level

Q: If n=18, (x-bar)=42, and s=17, construct a confidence interval at a 80% confidence level. Assune the…

A: We have given that,  Sample mean (x̄) = 42, standard deviation (s) = 17 and sample size (n) = 18…

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: A sample of size 16 was taken from a very large population. Sample statistics, x¯ and s, were used…

A: Formulae to find x¯ and s from confidence interval is as follows ,    x¯ = Lower limit +Upper limit…

Q: If n = 15, 43, and s = 9, construct a confidence interval at a 98 % confidence level. Assume the…

A:

Q: If n=16, ¯xx¯(x-bar)=46, and s=12, construct a confidence interval at a 95% confidence level. Assume…

A: Given n=16 x=46 s=12 CL=95% Data is normally distributed

Q: The scores on a standardized test are normally distributed. If a random sample of standardized test…

A: We know that, Confidence interval for population mean is given by :- ( x¯ -E ,  x¯+ E ) Where , x¯…

Q: A 95% confidence interval for the mean hours freshmen spent on social media per day was calculated…

A: Solution: From the given information, the 95% confidence interval for the mean hours freshmen spent…

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: A 95% confidence interval for a population mean was reported to be 148.69 to 155.31. If σ = 15, what…

A: given data 95% ci for mean : (148.69,155.31)σ = 15n = ?

Q: If n=14, (x-bar)=37, and s=7, construct a confidence interval at a 98% confidence level. Assume the…

A: Given,n=14x¯=37s=7degrees of freedom(df)=n-1df=14-1=13α=1-0.98=0.02α2=0.01t0.01(13)=2.650     (from…

Q: If n=15, ¯xx¯(x-bar)=30, and s=2, construct a confidence interval at a 98% confidence level. Assume…

A: Given Sample size n = 15  degree of freedom = n-1 =14 x the level of confidence interval   98 %…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: Find the following. Enter your answer rounded to at least two decimals. Z(a/2) for the 92%…

A: Answer: From the given data, 92%confidence interval,

Q: If n=19, ¯xx¯(x-bar)=37, and s=13, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n=22, ¯xx¯(x-bar)=46, and s=8, construct a confidence interval at a 98% confidence level. Assume…

A: It is given that mean and standard deviation are 46 and 8, respectively.

Q: n=31, ¯xx¯(x-bar)=30, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

A:

Q: -cientists tested each in a sample of 4 alleles of antigen-produced protein for level of peptide.…

A: The given value of n is 4, the sample mean is 1.49 and the sample standard deviation is 0.15.

Q: The heights of American women are normally distributed. If a random sample of American women is…

A: Point estimate: The population parameter which is estimated by using sample statistic is termed as…

Q: A sample of 23 plants was taken and the mean height was 27 cm. A 95% confidence interval for the…

A: From the given information, The 95% confidence interval for the true mean height of plants of that…

Q: Identify the t-score for a 90% confidence interval if the sample size is 25. t = The answer isnt…

A: We have given that Confidence level (c) = 90% = 0.90 Significance level (α) = 1 - c = 1 - 0.90 =…

Q: sample of 16 students was taken from university. These students spent an average of $170 on books…

A:

Q: If n=24, ¯xx¯(x-bar)=49, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A:

Q: If n=17, (x-bar)-45, and o =12, construct a confidence interval at a 80% confidence level. Assume…

A: Given X-bar=45 S=12 n=17

Q: Find the following. z a/2 at the 86% confidence interval

A:

Q: 1. A survey was taken by Automobile Company. One of the questions was: "What is your average daily…

A:

Q: A sample of size 84 was taken from a very large population. Sample statistics, x¯ and s, were used…

A:

Q: A sample of 50 students was taken from the local university. These students spent an average of R170…

A: Given information- Sample size (n) = 50 Mean x̅ = R170 Standard deviation (s) = R25.50 Significance…

Q: A 95% confidence interval forp is given as (0.34,0.66). How large was the sample used to construct…

A: Formula for the sample size needed to estimate a population proportion is

Q: Last year your professor taught economics courses to N = 200 students. From this group you randomly…

A:

Q: The number of television sets coming off a production line each day is known to have a standard…

A:

Q: A human resource manager wants to see if there is a difference in the proportion of minority…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: Find the 95% confidence interval (CI) and margin of error (ME) of the true mean weights of male…

A: As the population standard deviation is unknown, the t-test statistic to be used for estimating the…

Q: A newspaper reported that 90​% of people say that some coffee shops are overpriced. The source of…

A:

Q: A sample of size 16 was taken from a very large population. Sample statistics, x¯ and s, were used…

A:

Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: If n=15, ¯xx¯(x-bar)=33, and s=19, construct a confidence interval at a 80% confidence level. Assume…

A: Given' :  sample mean xbar=33  sample size n=15  sample standard deviations s=14  then to find 80%…

Q: A sample of 30 beams has an average strength of 1908.8 lbs. and s = 327.1. what is the 95%…

A:

Q: If n=28, (x-bar)=45, and s-8, construct a confidence interval at a 99% confidence level. Assume the…

A: Given that.  Sample size n =28 Sample mean=45 Standard deviation =8

Q: Out of a survey of 3200 people who own a hot tub, only 70% use it at least once each week. This was…

A: Solution: From the given information, p-hat is 70% and the margin of error is E=1.7%.

Q: Find the following. Enter your answer rounded to at least two decimals. Z/2 for the 88% confidence…

A: GIVEN DATA,WE HAVE TO FIND OUT THE VALUE OF OF Z CRITICAL VALUE FOR GIVEN DATA HERE CONFIDENCE…

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100