A sample of Cl₂ gas has a volume of 17.0 L at a pressure of 1.50 atm and a temperature of 23 °C. What volume, in liters, will the gas occupy at 3.50 atm and 281 °C? Assume ideal behavior. V- L

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**Problem Statement:**

*A sample of Cl₂ gas has a volume of 17.0 L at a pressure of 1.50 atm and a temperature of 23 °C.*

*What volume, in liters, will the gas occupy at 3.50 atm and 281 °C? Assume ideal behavior.*

**Answer:**

*V =* [Enter the calculated volume in liters] *L*

**Explanation:**

To solve this problem, apply the Ideal Gas Law and the combined gas law. You'd need to convert temperatures to Kelvin and use the formula:

\[
\frac{{P_1 \cdot V_1}}{{T_1}} = \frac{{P_2 \cdot V_2}}{{T_2}}
\]

Where:
- \(P_1\), \(V_1\), and \(T_1\) are the initial conditions.
- \(P_2\), \(V_2\), and \(T_2\) are the conditions under which you want to find the new volume \(V_2\). 

Convert temperatures from Celsius to Kelvin by adding 273.15.

Given:
- \(P_1 = 1.50 \, \text{atm}\)
- \(V_1 = 17.0 \, \text{L}\)
- \(T_1 = 23\, ^{\circ}\text{C} = 296.15 \, \text{K}\)

- \(P_2 = 3.50 \, \text{atm}\)
- \(T_2 = 281 \, ^{\circ}\text{C} = 554.15 \, \text{K}\)

Substitute these values into the equation to solve for \(V_2\).
Transcribed Image Text:**Problem Statement:** *A sample of Cl₂ gas has a volume of 17.0 L at a pressure of 1.50 atm and a temperature of 23 °C.* *What volume, in liters, will the gas occupy at 3.50 atm and 281 °C? Assume ideal behavior.* **Answer:** *V =* [Enter the calculated volume in liters] *L* **Explanation:** To solve this problem, apply the Ideal Gas Law and the combined gas law. You'd need to convert temperatures to Kelvin and use the formula: \[ \frac{{P_1 \cdot V_1}}{{T_1}} = \frac{{P_2 \cdot V_2}}{{T_2}} \] Where: - \(P_1\), \(V_1\), and \(T_1\) are the initial conditions. - \(P_2\), \(V_2\), and \(T_2\) are the conditions under which you want to find the new volume \(V_2\). Convert temperatures from Celsius to Kelvin by adding 273.15. Given: - \(P_1 = 1.50 \, \text{atm}\) - \(V_1 = 17.0 \, \text{L}\) - \(T_1 = 23\, ^{\circ}\text{C} = 296.15 \, \text{K}\) - \(P_2 = 3.50 \, \text{atm}\) - \(T_2 = 281 \, ^{\circ}\text{C} = 554.15 \, \text{K}\) Substitute these values into the equation to solve for \(V_2\).
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