A sample of 30 observations is selected from a normal population. The sample mean is 59, and the population standard deviation is 8. Conduct the following test of hypothesis using the 0.02 significance level.H0: μ = 62H1: μ ≠ 62 a. Is this a one- or two-tailed test? (One-tailed or Two-tailed) b. What is the decision rule? (Reject H0 if −2.326 < z < 2.326 or Reject H0 if z < −2.326 or z > 2.326) c. What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)The value of the test statistic is d. What is your decision regarding H0? (Reject H0 or Fail to reject H0) e-1. What is the p-value? (Round your z value to 2 decimal places and final answer to 4 decimal places.)The p-value is e-2. Interpret the p-value? (Round your z value to 2 decimal places and final answer to 2 decimal places.)There is a % chance of finding a z value this large by "sampling error" When H0 is true.
A sample of 30 observations is selected from a normal population. The sample mean is 59, and the population standard deviation is 8. Conduct the following test of hypothesis using the 0.02 significance level.
H0: μ = 62
H1: μ ≠ 62
a. Is this a one- or two-tailed test? (One-tailed or Two-tailed)
b. What is the decision rule? (Reject H0 if −2.326 < z < 2.326 or Reject H0 if z < −2.326 or z > 2.326)
c. What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
The value of the test statistic is
d. What is your decision regarding H0? (Reject H0 or Fail to reject H0)
e-1. What is the p-value? (Round your z value to 2 decimal places and final answer to 4 decimal places.)
The p-value is
e-2. Interpret the p-value? (Round your z value to 2 decimal places and final answer to 2 decimal places.)
There is a % chance of finding a z value this large by "sampling error" When H0 is true.
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