College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A ruler can be reasonably read down to the nearest millimeter, while a Vernier caliper can be read to the nearest 0.1 millimeter. Suppose you want to measure an object with nominal length of 2 cm with a precision as close to 1% as possible. Which instrument can you use? (You can do a calculation to figure this out.)
a. The ruler or the caliper.
b. The ruler.
c. The caliper.
d. Neither, you would need a micrometer.
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- Given a set of length measurements: 62.1, 62.5, 61.7, 62.6, 62.7, 61.9 cm. Find the standard error for length measurement.arrow_forwardInstrument Ruler Quantities Diameter Units m Meas #1 Meas #2 Meas #3 Meas #4 Meas #5 Meas #6 0.011 0.017 0.019 0.016 0.009 0.021 Vernier Caliper Micro-meter Diameter Diameter 0.0120 0.0166 0.0182 0.0151 0.0100 0.0225 0.01268 0.01745 0.01904 0.01587 0.00947 0.02221 Ruler Volume 7.0E-07 2.6E-06 3.6E-06 2.1E-06 4.E-07 4.8E-06 Measurements: diameter and volume. Results: mass Vernier Caliper Volume Measurements: diameter and mass. Results: volume O Measurements: diameter and mass. Results: none. 9.05E-07 2.40E-06 3.16E-06 1.80E-06 5.24E-07 5.96E-06 Among this data, what is considered raw measurement and plain result? Micro-meter Volume 1.067E-06 2.782E-06 3.614E-06 2.093E-06 4.45E-07 5.736E-06 Measurements: diameter measured with the ruler only and mass. Results: volume. Scale Mass kg 0.00850 0.02080 0.02720 0.01680 0.00389 0.04423arrow_forwardmin where Given the equation p= m =13.75±0.06 and n =0.0787+0.0007. What is the absolute uncertainty in P? Select one: O a. 285±5 O b. 285±8 O c. 285+7 O d. 285±6arrow_forward
- a. 2πR2+2πRh2πR2+2πRh b. 2πR2+2πh2πR2+2πh c. πR2hπR2h d. πD2+πDhπD2+πDh e. 2πR+2πRharrow_forwardI have an homework where I was asked to get a generic 12 in/30 cm ruler and then answer the question in bold: Look at the smallest division and record what the uncertainty ▲x is of your tool. I am not sure how to ansswer this. Note: the previous question asked me to choose a unit of measurement on our tool which is the ruler and I choose inches (I hope that is a unit of measurement).arrow_forwardQ.5. What could be the possible reasons for errors in measurements?arrow_forward
- 1. The floor of a rectangular building has an area of 120 square meter. The length of the floor / is 4m bigger than its width, w. Solve for I. Hint: Start with the equation of the area in terms of I. What kind of equation do you get? /= 48.11 X feet ! No, that's not the correct answer.arrow_forwardGiven that the Diameter of Earth is about 7200 miles, how many Earths would fit across the Sun? You turn toward the east, seeing the full moon rising. You find that half of your finger tip at arm's length also covers the diameter of the Moon! Given that the diameter of the Moon is about 2160 miles, approximately how far from Earth is the Moon in miles and km according to your calculations?arrow_forwardboth plsarrow_forward
- 4.) Use your linear fit parameters above to state the best estimate of the equation for this line. Remember the equation of the line is y = mx +b where m is the slope and b is the y-intercept. Include units. v(t) (m/s) = Error Analysis: t+ The theoretical value of the slope is 20.45 m/s². 5.) Basic error analysis: (Read page 2 of Error Analysis handout). Compute a % error between the theory value and the most probable experimental value . % error = Q2.) Is the % error positive or negative? What does that tell you? (Read page 3 of Error Analysis handout). Q3.) Can you say if this % error value is "small" or "large"? So can you say if there evidence of discrepancy or no? Do you see the problem with this basic approach?arrow_forwardy1 = sin(pi(x) - 2(pi)(t))......y2 = sin(pi(x)/2 + 2(pi)(t))arrow_forward
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