A rubber bullet of mass m = 0.025 kg traveling at velocity vo50 m/s hits15 kg initially hanging at rest from a massless rope.an iron block of mass MAfter the collision, the bullet bounced straight back at a speed of v135 m/s.MMV1hThe effect of gravity on the bullet alone can be ignored. To what maximumheight h will the iron block reach after the collision? (Assume that the roperemains tight during the entire process).

Name: A rubber bullet of mass m = 0.025 kg traveling at velocity vo50 m/s h
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Description: A rubber bullet of mass m = 0.025 kg traveling at velocity vo50 m/s hits15 kg initially hanging at rest from a massless rope.an iron block of mass MAfter the collision, the bullet bounced straight back at a speed of v135 m/s.MMV1hThe effect of gravi

Mass of bullet ( m ) = 0.025 kg Velocity of bullet ( v0 ) = 50 m/s Mass of iron block ( M )= 15 kg…

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A rubber bullet of mass m = 0.025 kg traveling at velocity vo an iron block of mass M = 15 kg initially hanging at rest from a massless rope. After the collision, the bullet bounced straight back at a speed of vi = 35 m/s. 50 m/s hits %3| M h The effect of gravity on the bullet alone can be ignored. To what maximum height h will the iron block reach after the collision? (Assume that the rope remains tight during the entire process).

A rubber bullet of mass m = 0.025 kg traveling at velocity vo an iron block of mass M = 15 kg initially hanging at rest from a massless rope. After the collision, the bullet bounced straight back at a speed of vi = 35 m/s. 50 m/s hits %3| M h The effect of gravity on the bullet alone can be ignored. To what maximum height h will the iron block reach after the collision? (Assume that the rope remains tight during the entire process).

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter9: Momentum And Its Conservation

Section: Chapter Questions

Problem 77A

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