College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Problem Description:**

A rubber ball, with a mass of 40.0 grams, is dropped from rest from a height of 1.20 m above the floor. It hits the floor and then reaches a maximum height of 80.0 cm when it comes back up again. In this problem, use \( g = 10.0 \, \text{m/s}^2 \).

**Questions:**

(a) The collision with the floor causes some mechanical energy to be lost (this energy generally ends up as thermal energy). How much mechanical energy is lost in this case?
- [ ] J

(b) What is the ball's speed, just as it leaves the floor on its way up?
- [ ] m/s

(c) What is the magnitude of the impulse experienced by the ball for the entire time it is in contact with the floor?
- [ ] kg \(\cdot\) m/s

**Guide for Solution:**

1. **Convert Units:**
   - Mass: \( 40.0 \, \text{grams} = 0.040 \, \text{kg} \).
   - Convert the maximum height from cm to meters: \( 80.0 \, \text{cm} = 0.80 \, \text{m} \).

2. **Calculate Initial Potential Energy:**
   - \( PE_{\text{initial}} = mgh = 0.040 \times 10.0 \times 1.20 \).

3. **Calculate Final Potential Energy:**
   - \( PE_{\text{final}} = mgh = 0.040 \times 10.0 \times 0.80 \).

4. **Determine Energy Loss:**
   - \( \text{Energy Lost} = PE_{\text{initial}} - PE_{\text{final}} \).

5. **Find Speed as it Leaves the Floor:**
   - Using energy conservation principles on the way up to find speed.

6. **Calculate Impulse:**
   - Impulse involves change in momentum and can be calculated by considering before and after collision velocities.

Follow these steps to find the answers to each question, applying necessary physics formulas for potential energy, kinetic energy, and momentum.
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Transcribed Image Text:**Problem Description:** A rubber ball, with a mass of 40.0 grams, is dropped from rest from a height of 1.20 m above the floor. It hits the floor and then reaches a maximum height of 80.0 cm when it comes back up again. In this problem, use \( g = 10.0 \, \text{m/s}^2 \). **Questions:** (a) The collision with the floor causes some mechanical energy to be lost (this energy generally ends up as thermal energy). How much mechanical energy is lost in this case? - [ ] J (b) What is the ball's speed, just as it leaves the floor on its way up? - [ ] m/s (c) What is the magnitude of the impulse experienced by the ball for the entire time it is in contact with the floor? - [ ] kg \(\cdot\) m/s **Guide for Solution:** 1. **Convert Units:** - Mass: \( 40.0 \, \text{grams} = 0.040 \, \text{kg} \). - Convert the maximum height from cm to meters: \( 80.0 \, \text{cm} = 0.80 \, \text{m} \). 2. **Calculate Initial Potential Energy:** - \( PE_{\text{initial}} = mgh = 0.040 \times 10.0 \times 1.20 \). 3. **Calculate Final Potential Energy:** - \( PE_{\text{final}} = mgh = 0.040 \times 10.0 \times 0.80 \). 4. **Determine Energy Loss:** - \( \text{Energy Lost} = PE_{\text{initial}} - PE_{\text{final}} \). 5. **Find Speed as it Leaves the Floor:** - Using energy conservation principles on the way up to find speed. 6. **Calculate Impulse:** - Impulse involves change in momentum and can be calculated by considering before and after collision velocities. Follow these steps to find the answers to each question, applying necessary physics formulas for potential energy, kinetic energy, and momentum.
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