A roller-coaster car of mass 1.50 x 10° kg is initially at the top of a rise at point @. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point ®. (a) Find both the potential energy of the system when the car is at points @ and ® and the change in potential energy as the car moves from point @ to point ®, assuming y = 0 at point ®. (b) Repeat part (a), this time choosing y = 0 at point ©, which is another 15.0 m down the same slope from point ®.

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Chapter1: Units, Trigonometry. And Vectors
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A roller-coaster car of mass 1.50 x 10° kg is initially at the top
of a rise at point @. It then moves 35.0 m at an angle of 50.0°
below the horizontal to a lower point ®. (a) Find both the
potential energy of the system when the car is at points @ and
® and the change in potential energy as the car moves from
point @ to point ®, assuming y = 0 at point ®. (b) Repeat
part (a), this time choosing y = 0 at point ©, which is another
15.0 m down the same slope from point ®.
Transcribed Image Text:A roller-coaster car of mass 1.50 x 10° kg is initially at the top of a rise at point @. It then moves 35.0 m at an angle of 50.0° below the horizontal to a lower point ®. (a) Find both the potential energy of the system when the car is at points @ and ® and the change in potential energy as the car moves from point @ to point ®, assuming y = 0 at point ®. (b) Repeat part (a), this time choosing y = 0 at point ©, which is another 15.0 m down the same slope from point ®.
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