A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm² lies along the x-axis between æ = 0 and a = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po ( 1 L² where po = 5 x 1o 42 · m. The end of the rod at a = 0 is at a potential Vo = 30 V greater than the end at æ = L. %3D A) What is the total resistance, in units of N, of the rod?

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(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm? lies along
the x-axis between æ = 0 and a = L. The material obeys Ohm's law, and its resistivity varies along the rod
according to p = Po ( 1
where po = 5 x 10 4 N - m. The end of the rod at a = 0 is at a potential
L2
Vo = 30 V greater than the end at x = L.
A) What is the total resistance, in units of N, of the rod?
Answer:
Transcribed Image Text:(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm? lies along the x-axis between æ = 0 and a = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po ( 1 where po = 5 x 10 4 N - m. The end of the rod at a = 0 is at a potential L2 Vo = 30 V greater than the end at x = L. A) What is the total resistance, in units of N, of the rod? Answer:
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