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- m m 2 Traveling with an initial speed of 128 kr, a Cessna 172 accelerates at 6000kr during level flight. How long will it take to reach a speed of 226kr ? Give your answer in seconds (s).Newton's law of universal gravitation is represented by Mm F = G• where F is the gravitational force, M and m are masses, and r is a length. Force has the Sl units kg - m/s?. What are the Sl units of the proportionality constant G?a) What is the average speed in kilometers per second of the Earth around the sun, given that the radius of the Earth's orbit is 1.5×108km? b) What is the average velocity of the Earth over a year's time?
- iven: V = 20-(Horizontally) Vyi = 0-,Required: the horizontal distance of the stone. Vxi = 20. 1 Step1: y yi+Vyit-gt2 30%= 20 +0- 10 x t? t= 2.0 seconds. Step2: X = X, + vVxit = 0+ 20 x 2.0 = 40 meter. - Correct Answer is A. Problem (4): A fire fighter 32.0 m away from a building, directs a stream of water from a fire hose at an angle of 37 with speed of 40.0 m/s. At what height does the stream hit the building? A.21.9 m B. 22.5 m C. 19.1 m D. 20.9 m Solution: (X;%3D0 Xf = 32 m %3D Given: Required: the height the stream will reach on the building. Vi = 40- 0;=370 Vxi =V; Cos 0 = 40 x cos 37 = 31.9- Step1: Vyi = Vị sin 0 = 40 x sin 37 = 24.1- %3D %3D %3D %3D Step2: X = X, + Vxit %3D 32 =0+31.9 xt t%3D 1.0 second Step3: y = y,+ Vyjt-gt 2812 3D0+ (24.1 x 1.0)-x 10 x 12) 3D19.1 meter. 3 Correct Answer is C.. 59 S.Given H f(t) where H is the height in meters of an object and t is the time in seconds since it was launched, which of the following is the best interpretation of f(4) 8? 04 seconds after the object is launched it is traveling 8 meters per second. O The object travels 8 meters for every 4 seconds. O The object is 32 meters in the air. O The object travels 4 meters for every 8 seconds. 08 seconds after the object is launch it is 4 meters in the air 08 seconds after the object is launched it is traveling 4 meters per second. 04 seconds after the object is launched it is 8 meters in the air,magnitude gravitational force (between a planet with mass 9.00 * 10 ^ 24 and moon, with 2.40 * 10 ^ 22 average distance between their canters 2.10 * 10 ^ 8* m b) ? is the moon's acceleration in m/s^ 2 ) toward the planet(Enter the magnitude. ) m/s^ 2 the planets acceleration (in m/s^ 2 ) the moon?
- NMU E X O Launch X WA 220-03 X * Cengag x M Inbox (2 x M Fwd: Ple X a Amazor x a Amazor X Psychol x How to X -> i webassign.net/web/Student/Assignment-Responses/last?dep=26014027#question4038310_20 E Apps O Current Student Inf... N Technology Suppor. G A mega-city is defi... O IT Services N My NMU 9 MyUser O NMU EduCat™M N NMU Library G NMU Webmail N NMU >> Consider the three vectors A, B, and C (in the same plane) shown in the figure. B Graphically determine the following and select your answers from the vectors (1 through 7) shown below. Note that case 7 represents the null vector. 2 3 (a) A+B + C 1 (b) -А - В - С 2 (c) A+ 2C + B ---Select--- v (d) A + 2B + C ---Select--- v (e) A + 2B + 2C |---Select--- v Viewing SaI/ed Work Revert to Last Response 8:04 PM O Type here to search )コ G 2/5/2021 22 .. + 田 ↑An object is dropped from a tower, 256ft above the ground. The object's height above ground x seconds after the fall is s(x)=256−16x2.About how long does it take the object to hit the ground? What is the object's velocity at the moment of impact? It takes nothing sec for the object to hit the ground. (Round to the nearest tenth as needed.)A particle travels around a circular path having a radius of 38 m. If it is initially traveling with a speed of 10 m/s and its speed then increases at a rate of (0.05 v) m/s 2, determine the magnitude of the particle’s acceleration at t = 2 s. Round your answer to 2 decimal places
- Figure E1.28 у В (15.0 m) D (10.0 m) 30.0° 53.00 25.0° Č (12.0 m) A (8.00 m) f. Solve for A x C • D.A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time t is h(t) : 30t – 4.9t2 m. Compute the stone's average velocity ū in m/s over the time intervals [2, 2.01], [2,2.001], [2,2.0001] and [1.9999, 2], [1.999, 2], [1.99, 2]. (Use decimal notation. Give your answers to three decimal places.) Ū12,2.01] = m/s Ü12,2.001] = m/s U12,2.0001] = m/sA car is traveling at 50 mi/hmi/h down a highway. What magnitude of acceleration does it need to have to come to a complete stop in a distance of 200 ftft? Express your answer in miles per hour squared. What magnitude of acceleration does it need to stop in 200 ftft if it is traveling at 100 mi/hmi/h? Express your answer in miles per hour squared.