College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Concept explainers

Electric Charges and Fields
One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.
Question

Please solve the problem in the pictures

A ring-shaped conductor with radius a = 2.20 cm has a total positive charge Q = 0.122 nC uniformly distributed around it. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Field of a ring of charge. Figure e a 0 dQ ds √x² + a² X dEy dE 1 of 1 dE X ▼ Part A What is the magnitude of the electric field at point P, which is on the positive x-axis at x = 45.0 cm ? Express your answer in newtons per coulomb. IV—| ΑΣΦ E = Submit Part B Request Answer What is the direction of the electric field at point P? +x-direction -x-direction Submit Request Answer ? N/C
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Transcribed Image Text:A ring-shaped conductor with radius a = 2.20 cm has a total positive charge Q = 0.122 nC uniformly distributed around it. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Field of a ring of charge. Figure e a 0 dQ ds √x² + a² X dEy dE 1 of 1 dE X ▼ Part A What is the magnitude of the electric field at point P, which is on the positive x-axis at x = 45.0 cm ? Express your answer in newtons per coulomb. IV—| ΑΣΦ E = Submit Part B Request Answer What is the direction of the electric field at point P? +x-direction -x-direction Submit Request Answer ? N/C
Part C A particle with a charge of 3.00 μC is placed at the point P described in part A. What is the magnitude of the force exerted by the particle on the ring? Express your answer in newtons. F = IVE ΑΣΦ Submit Request Answer Part D +x-direction What is the direction of the force exerted by the particle on the ring? -x-direction Submit Request Answer ? P Pearson N Review | Constants
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Transcribed Image Text:Part C A particle with a charge of 3.00 μC is placed at the point P described in part A. What is the magnitude of the force exerted by the particle on the ring? Express your answer in newtons. F = IVE ΑΣΦ Submit Request Answer Part D +x-direction What is the direction of the force exerted by the particle on the ring? -x-direction Submit Request Answer ? P Pearson N Review | Constants
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