A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has radius 10 cm and rolls from rest without slipping. The coefficient of kinetic friction is 0.2. Given that the rotational inertia of a ring is MR², calculate Ring R = 10 cm M = 0.2 kg 0 = 30° (a) the magnitude of friction between the ring and plane. (b) the magnitude of torque applied on the ring. (c) the magnitude of angular acceleration of the ring. (d) the magnitude of angular momentum after 2 s. (e) the kinetic energy after 2 s.

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Chapter11: Angular Momentum
Section: Chapter Questions
Problem 27P: A solid cylinder of radius 10.0 cm rolls down an incline with slipping. The angle of the incline is...
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A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has
radius 10 cm and rolls from rest without slipping. The coefficient of kinetic friction is 0.2.
Given that the rotational inertia of a ring is MR², calculate
Ring
R = 10 cm
М -D0.2 kg
0 = 30°
(a) the magnitude of friction between the ring and plane.
(b) the magnitude of torque applied on the ring.
(c) the magnitude of angular acceleration of the ring.
(d) the magnitude of angular momentum after 2 s.
(e) the kinetic energy after 2 s.
Transcribed Image Text:A ring of mass 0.2 kg is placed at the top of an inclined plane with angle 0 = 30°. The ring has radius 10 cm and rolls from rest without slipping. The coefficient of kinetic friction is 0.2. Given that the rotational inertia of a ring is MR², calculate Ring R = 10 cm М -D0.2 kg 0 = 30° (a) the magnitude of friction between the ring and plane. (b) the magnitude of torque applied on the ring. (c) the magnitude of angular acceleration of the ring. (d) the magnitude of angular momentum after 2 s. (e) the kinetic energy after 2 s.
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