A rhombus ABCD is such that: 1. A = (-2, 1, 2) 2. B lies on the line L with vector equation: -2 -6 1 +s-2 2 -2 3. The diagonals intersect at M = (-1, 2, 1) Find the coordinates of the remaining vertices B, C, D. B = (0,0,0) C = (0,0,0) D = (0,0,0) II

4(2). Please show your calculations & explain steps by steps. Determines the vector equation: A) from the line in R2 that goes through the points (3, -6) and (0, -1). B) of the plan in R3 that contains the points (-6, 1, 0), (4, -3, 5) ret (-7, -2, -4).

Which equations below represent the line in R³ that passes through the point (-3,5,-5) and is parallel to the vector 3i + 4j + 6k? You may select more than one equation. Or(t): +t OF(t) = + t Ox=3+3t; y = 5 + 4t; z = = 5 + 6t - OF(t): = -3, 5, -5> +t OF(t) = +t 1 - x=3+ 6t; y = 5 + 8t; z = 5+ 6t OF(t)= +t OF(t)= + t -

A line contains the points P=(−6,−2,−3)P=(-6,-2,-3) and Q=(−4,−3,−6)Q=(-4,-3,-6). A vector equation of this line is →x=−−→OP+t−−→PQx→=OP→+tPQ→, where OO is the origin.If t=2t=2, what point does this give us from the equation?