A researcher wishes to estimate the mean length of North American adult bullfrogs. To do so, a random sample of 69 frogs is selected. Their mean length is 130.1 cm. We will assume that the population lengths are normally distributed with population standard deviation 24.2 cm. Construct the 99% confidence interval for the mean population length. Show your relevant steps below. Intermediate Calculations: z value = (Enter the number.) (cm) (cm) Standard Error = Maximum Error of Estimate : Final Answer: The 99% Confidence Interval of the true mean length of North American bullfrogs is (Lower Limit, Upper Limit) cm, cm)

Find the lower limit of 95% confidence interval.    An SRS of 36 students were taken from high schools in a particular state. The average test score of the sampled students was 60 with a standard deviation of 13.26. Give the lower limit of the interval approximation.

You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)

A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence assuming s=13.4 based on earlier​ studies? Suppose the doctor would be content with 95% confidence. How does the decrease in confidence affect the sample size​ required?

A researcher wants to make a 95% confidence interval for the population mean. She wants the maximum error of estimate to be within 4.8 of the population mean. The population standard deviation is 18.65. What would be the sample size the yield a maximum error of estimate within 4.8 of the population mean?

You would like to make an interval estimate of a population mean from a sample of size 25. Assume the population standard deviation is 6. Assuming 98% Confidence, what is the margin for error for the estimate.

Assume that a sample is used to estimate a population mean μ . Find the 95% confidence interval for a sample of size 582 with a mean of 34.8 and a standard deviation of 8.1. Enter your answers accurate to three decimal places. Confidence Interval = (        ,       )