A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of  275  individuals who had been taking the drug is questioned;  231  of them found relief from depression. Based upon this, compute a  95%  confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limit and upper limit of the  95%  confidence interval.

Q: during production of detergent. In people with no lung dysfunction, a typical air flow rate is 0.80.…

A: As the population standard devoation is known, we will use z distribution. The value of z at the…

Q: test. It was found that 80 of them scored higher than 100. Based on this, compute a 95% confidence…

A: According to the given information in this question We need to construct 95% confidence interval

Q: A random sample of 300 college freshmen found that 112 of them own an iPhone.  Find a 95% confidence…

A: Given, Favorable Cases XX = 112112 Sample Size NN = 300300

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: In 2016 the CDC wanted to estimate the proportion of adults who are smokers in the U.S. The…

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Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: The objective of this question is to construct a 95% confidence interval for the proportion of adult…

Q: I've asked 91 students on Monday whether they did their homework over the weekend. 20 of them said…

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Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: Many high school students take the AP tests in different subject areas. In one year, of the 144,140…

A: given data  n1 = 144140   x1 = 84545p^1 = x1n1 = 84545144140 = 0.5865 n2 = 216298    x2 = 126501p^2…

Q: A poll of n = 500 randomly selected elementary school students resulted in 110 of them stating…

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Q: A survey of 1,000 adults showed 58% believed the driving age should be changed from 16 years of age…

A: Provided information: Number of adults in a survey = 1000 58% believed the driving age should be…

Q: A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of…

A: Solution: Given information: n1= 230 Sample size of people iving in Seattle n2= 172  Sample size of…

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: sample of 97 psychology graduates found an average salary of $71 K/year. Assume ?=$14 K/year. Find…

A: Given Z score 90% confidence interval=1.645 Sigma=14 n=97

Q: The General Social Survey asked 1294 people whether they performed any volunteer work during the…

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Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Solution: It is given here:

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

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Q: m what their favorite color was. 23 people said their favorite color is blue. Using this sample,…

A: Sample proportion is the fraction of successful samples and total number of samples. Here,  Total…

Q: A study investigated ways to prevent staph infections in surgery patients. The researchers examined…

A: From the provided information, Sample size (n) = 100 From which 88 patients tested positive for…

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

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Q: construct a 95% confidence interval for the true population proportion of people with kids.

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Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: A study investigated ways to prevent staph infections in surgery patients. The researchers examined…

A: Given that, x=86,n=100 The sample proportion is, p^=xn  =86100  =0.86

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

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Q: A recent study indicated that 24% of women over 55 are widows. A researcher wishes to estimate with…

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Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: In a clinical trial of a certain drug, 30 subjects experience headaches among the 220 subjects…

A: Step 1: State the given: number of favorable cases, x = 30sample size, n = 220confidence level =…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Solution

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

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Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

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Q: A smart phone manufacturer is interested in constructing a 99% confidence interval for the…

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Q: Out of 500 people sampled, 330 had kids. Based on this, construct a 90% confidence interval for the…

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Q: Out of 500 people sampled, 95 had kids. Based on this, construct a 90% confidence interval for the…

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Q: A student found that in a random sample of 300 people in a town, 105 play sports. Based on this…

A: Given that, X = 105 N = 300 90% confidence level

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

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Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: identify the t-score for a 90% confidence interval if the sample size is 31.        t=

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