A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 135 students who averaged 39.5 texts per day. The standard deviation was 14.9 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? z t  distribution. b. With 90% confidence the population mean number of texts per day is between ____ and  ____ texts. c. If many groups of 135 randomly selected members are studied, then a different confidence interval would be produced from each group. About ____ percent of these confidence intervals will contain the true population number of texts per day and about ____ percent will not contain the true population mean number of texts per day.

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A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. part a. Is this a one-sided or two-sided test? part b. What is the standard error for this problem? part c. How many degrees of freedom do we have for this problem? part d. What is the test statistic, t, for this problem? Based on your test statistic and degrees of freedom, the p-value will be between what two values? (If you cannot find the exact df in the table, round down to be safe. So if you have 38 df, round down to 30df.) Group of answer choices The p-value is between .1 and .05 The p-value is between .05 and .025 The p-value is between .025 and .01 The p-value…

Consider the data from the Anthropology 105 class.  The mean for women is 64.33 in and the standard deviation is 2.64 in. The average height of men in the US is approximately 5ft 10in. What proportion of women represented here are shorter than the average man?