A researcher has estimated a linear model to study the effect of weekly household income x, (in $100) on weekly household expenditure on food y, (in $). Using a i i sample of size N = 40, she found that = 83.42 + 10.21x,, R²=0.384 i (43.41) (2.09) and N Σ(y₁ - y)² = 500,000 and the sample mean of x, is 19.605. Then, i=1 i N * Σ 6-5) 2= 58,000 i=1 Oc. O d. N i=1 N i=1 (-y)² = 96,000 i (-y)²=192,000 N i=1 i (-y)²=384,000 i
A researcher has estimated a linear model to study the effect of weekly household income x, (in $100) on weekly household expenditure on food y, (in $). Using a i i sample of size N = 40, she found that = 83.42 + 10.21x,, R²=0.384 i (43.41) (2.09) and N Σ(y₁ - y)² = 500,000 and the sample mean of x, is 19.605. Then, i=1 i N * Σ 6-5) 2= 58,000 i=1 Oc. O d. N i=1 N i=1 (-y)² = 96,000 i (-y)²=192,000 N i=1 i (-y)²=384,000 i
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.2: The Least Square Line
Problem 1E
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Unsure about the answer , and could you please explain me the procedure? I am a little bit confused.
![A researcher has estimated a linear model to study the effect of weekly household
income x (in $100) on weekly household expenditure on food y, (in $). Using a
i
i
sample of size N = 40, she found that
y = 83.42 + 10.21x₁, R²=0.384
(43.41) (2.09)
N
and Σ(y₁ - y)² = 500,000 and the sample mean of x, is 19.605. Then,
i=1
i
O a. ₁ (-y)² = 58,000
i=1
i
N
Ο Φ. Σ. 6-5) 2=96,000
i=1 i
C.
Σ(-y)² = 192,000
i=1
O d. (-y)² = 384,000
i=1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cecaeef-2185-4d64-a3b2-3f78810f9007%2F6e74311e-9b8c-414e-9c06-64c72e5745f2%2F019yw4c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A researcher has estimated a linear model to study the effect of weekly household
income x (in $100) on weekly household expenditure on food y, (in $). Using a
i
i
sample of size N = 40, she found that
y = 83.42 + 10.21x₁, R²=0.384
(43.41) (2.09)
N
and Σ(y₁ - y)² = 500,000 and the sample mean of x, is 19.605. Then,
i=1
i
O a. ₁ (-y)² = 58,000
i=1
i
N
Ο Φ. Σ. 6-5) 2=96,000
i=1 i
C.
Σ(-y)² = 192,000
i=1
O d. (-y)² = 384,000
i=1
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