A register can store the maximum number as 2047 in unsigned binary number. Find out the binary equivalent of 435 and -780 in signed magnitude and 2's complement representation, assuming the number will be stored in the same register.
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A register can store the maximum number as 2047 in unsigned binary number. Find out the binary equivalent of 435 and -780 in signed magnitude and 2's complement representation, assuming the number will be stored in the same register.
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- b) There are five binary or hexadecimal numbers and six decimal conversions. Draw a line to connect each binary/hexadecimal to decimal number. Binary/Hexadecimal Decimal 4E 78 11011010 157 10011101 167 A7 25 19 218Topic is about shift registers in electrical engineering. 1. What is the main functional purpose of a register? We are looking for the specifics of what a register does in isolation, not with respect to applications. 2. In what cases might we use serial and parallel inputs/outputs? 3. Describe the purpose of the debouncer in your own words. 4. Is an SN5474 the same as an SN 7474? If not, how do they differ?B. step. Convert the decimal number (48.375) 10 to binary. Show your work step by
- The 3-bit shift register is shifted five times to the right with the serial input being 1011101. What is the content of the register? (Write your answer using only 0s and/or 1s.)Draw a flow diagram for a 2-bit binary counter/clock that counts from 0 to 3 in decimal system using loops (do not only use sequential blocks). Hint: look for patterns. Bit 1 Bit 0 1 1Convert (26)10 into a binary number Convert (26)10 into a binary number Convert (10110)2 into a decimal number. The Decimal Equivalent of the given Octal Number 127.4. is ------------- The Decimal Equivalent of the given Hexa Decimal Number (B65F)is ------------ Convert decimal 56 to binary Convert (0.6875)10 to (-------)2 Convert 362.358 into a decimal number Convert 42A.1216 into a decimal number
- USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…To convert the decimal number 30 to a 8-bit binary number, use the following representation methods: Contrary to one's complement: b) Excess-M:?Logic effort and parasitic delay
- You are using a signed 8-bit ALU to do the following arithmetic operations. Assume two numbers in binary are, a = (0110 1111)2 and b = (0110 0100)2. 6+4+5=15 (i) C = a + b (ii) D = a - b1. Gray code to Binary converter: Gray code is one of the codes used in digital systems. It has the advantage over binary numbers that only one bit in the code word changes when going from one number to the next. (See Table 1). Design a combinational circuit with 4 inputs and 4 outputs that converts a four- bit gray code number into an equivalent four-bit Binary number. Use Karnaugh map technique for simplification. Use LogicWorks for pre-lab demonstrations. Select the library "7400dev.clf* in the Parts Palette and then select the XOR chip 74-86. This would give you a set of 4 XOR's as shown in Fig. 1, just like the hardware chip 74-86. You could use as many as needed from these XOR gates in your design. Get back to ALL LIBRARIES and select switches for the inputs and Binary Probes as indicators of the outputs. Verify your design in the pre-Lab. During the Lab construct the circuit and verify its operations.Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C