A recent survey showed that among 650 randomly selected subjects who completed 4 years of college, 142 smoke and 508 do not smoke. Determine a 99.9% confidence interval for the true proportion of the given population that smokes. 99.9% CI: _____to ______

Q: A 93.32% Cl is given as (2.5, 3.5). From this information, find a 95% confidence interval (yes, this…

A: The provided information is as follows:The 93.32% confidence interval is (2.5,3.5).

Q: recent survey showed that among 725 randomly selected subjects who completed 4 years of college, 139…

A: Given that  n = 725 , Smoke = 139 , Not smoke = 586

Q: Each student drew a simple random sample of fifty students and created a 99% condfidence interval…

A: It is given that student has drawn a simple random sample of fifty students and created a 99%…

Q: Of 363 randomly selected medical students, 20 said that they planned to work in a rural community.…

A:

Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: When 460 junior college students were surveyed, 100 said they have a passport. Construct a 95%…

A: Given that there are 460 junior college students and 100 said they have a passport. That is, n=460…

Q: Out of 100 people sampled, 77 had kids. Based on this, construct a 95% confidence interval for the…

A: We have to find 95% confidence interval for the true population proportion of people with kids.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: A 20-minute consumer survey mailed to 500 adults aged 25 to 34 included a $5 Starbucks gift…

A:

Q: Lindsey selected a random sample of 25 tomatoes at the farmer's market. The 95% confidence interval…

A: When Lindsey selected a random sample of 25 tomatoes at the farmer's market, she was aiming to…

Q: In a sample of 100,40 said they preferred Pepsi to Coke. A 95% confidence interval for the…

A:

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: A recent survey showed that among 850 randomly selected subjects who completed 4 years of college,…

A: I'm providing the solution below please do refer it and let me know if you have any queries…

Q: sample of 97 psychology graduates found an average salary of $71 K/year. Assume ?=$14 K/year. Find…

A: Given Z score 90% confidence interval=1.645 Sigma=14 n=97

Q: Out of 200 people sampled, 72 had kids. Based on this, construct a 90% confidence interval for the…

A: Givensample size(n)=200x=72sample proportion(p^)=xn=72200=0.36Confidence level=90%

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

A:

Q: In a survey of 2313 adults, 714 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given, In a survey of 2313 adults, 714 say they believe in UFOs. n=2313 x=714 Sample proportion:…

Q: Please answer number 11.

A: Sample mean =40(using the formula ‘=AVERAGE (A1:A8).Sample standard deviation, s = 5.5549(using the…

Q: In a sample of 100, 40 said they preferred Pepsi to coke. A 95% confidence interval for the…

A:

Q: A local health centre noted that in a sample of 400 patients, 80 were referred ta hospital. a.…

A: Given, n = 400            x = 80 Therefore, population proportion p^ = 80400 = 0.2 The critical…

Q: one city, 79.6% of the 8500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given n=8500

Q: 67% out of 150 pupils from school A passed an exam; 62% of 120 pupils at school B passed. Estimate…

A: Given : n1 = 150 n2 = 120 confidence level,c=0.9

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: the following sample was taken from a normally distributed population: 20,27,15,2016,22 and 13. A…

A:

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: A survey was conducted that asked 1007 people how many books they had read in the past year. Results…

A: given that,sample mean, x =12.2standard deviation, s =16.6sample size, n =1007standard error = sd/…

Q: A statistical study is made to compare the % of smokers in small rural towns to the overall smoking…

A: Given Information:n=1500x=285c=95%=0.95

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Each student in a class of 60 was randomly assigned one line of a random number table. Each student…

A: Given data There are total 10 digits [0 – 9] 5 odd digits 1,3,5,7,9 5 even digits 0,2,4,6,8…

Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…

A: We have given that,  Favorable cases (X) = 139 and Sample size    (n) = 725 Then,  We will find 95%…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: Commerce students were asked if they watch or listen to the state of the nation address (SONA), of…

A: Given: n= 220 ,x= 105 At 90.0 % confidence level , z score= 1.645 Need to find confidence interval…

Q: Construct the 90% confidence interval for the difference p1-p2 when x1=45, n1=85, x2=20, and n2=65.…

A: Given Information: x1=45n1=85x2=20n2=65c=90%=0.90

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A simple random sample of 500 students at UMass Boston is taken to estimate the percentage of all…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.