+ A Read aloud Fit to page Page view | I X $666.10 $593.84 $521.58 0.92 0.04 2 0.04 2 0.46 - Z -1.75 1.75 arch hp fa fs f6 T8 ho fo ASt 44 $ 4 & 3 5 7 Y P 00 8 LE + Fit to page nce interval for a mean. We use the formula for a m continuous random variable. The point estimate for the true population standard deviation because with 8 the confidence interval. xt(a/2) Vn to the formula, we have: 593.84 +1.75369.34 V80 и standard normal table by looking up 0.46 in the body of t n the side and top of the table; 1.75. The solution for the in = 593.84 + 72.2636 = (521 .57, 666.10) u $ 521.58< u $ 666.10 8

List below are the speeds (mi/h) measured from the southbound traffic on I-280, the speed limit is 65 mph. 62, 61, 61, 57, 61, 54,59, 58, 59, 69, 60, and 67 1.Construct a 99% confidence Interval 2. Construct a 90% interval 3. Explain what happen to the width of the confidence interval as the confidence level decreases

Describe about the INTERPRETATION OF A CONFIDENCE INTERVAL.

Just B please

Nabisco claims that Chip Ahoy Cookies have an x ̅=28.67 chocolate chips per cookie with a SD=2.67.  You randomly select 36 cookies from a new bag and carefully remove all the chocolate chips from each of the 36 cookies.  You find the mean of the chocolate chips for the 36 cookies is 24.27 chocolate chips per cookie.  Calculate the standard error for the chocolate chips in your experiment.  (round to the nearest hundredth).

Construct a 96% confidence interval if x=75 and n=200. Round your answers to 3 decimal places.

A poll of 1070 U.S. adults found that 563 U.S. adults, or 52.617% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Express all answers as percentages rounded to 2 decimal places. Do not write the percent sign. Margin of Error (as a percentage): Confidence Interval: Margin of Error (as a percentage): Confidence Interval: Now find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Margin of Error (as a percentage): Confidence Interval: % to O increases O stays roughly the same O decreases % to Finally, find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. and the precision of our estimate O decreases O increases O stays roughly the…

Explain what happens when finding the margin of error if all stays the sameexcept that the confidence interval increases.