A ray of light strikes a flat glass block at an incidence angle of 8₁ = 34.2°. The glass is 2.00 cm thick and has an index of refraction that equals n₂ = 2.00. (a) What is the angle of refraction, 82, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.) 16.3 X You know the index of refraction for air and the glass, as well as the angle of incidence, ₁. How does Snell's law relate these three variables to the unknown angle of refraction, 8₂? Be sure that your calculator is in degree mode. (b) with what angle of incidence, 03, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.) (c) with what angle of refraction, 4, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.)
A ray of light strikes a flat glass block at an incidence angle of 8₁ = 34.2°. The glass is 2.00 cm thick and has an index of refraction that equals n₂ = 2.00. (a) What is the angle of refraction, 82, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.) 16.3 X You know the index of refraction for air and the glass, as well as the angle of incidence, ₁. How does Snell's law relate these three variables to the unknown angle of refraction, 8₂? Be sure that your calculator is in degree mode. (b) with what angle of incidence, 03, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.) (c) with what angle of refraction, 4, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.)
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Reflection And Refraction Of Light
Section: Chapter Questions
Problem 16P
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Question
Transcribed Image Text:A ray of light strikes a flat glass block at an incidence angle of ₁ = 34.2º. The glass is 2.00 cm thick and has an index of refraction that equals ng = 2.00.
(a) What is the angle of refraction, 02, that describes the light ray after it enters the glass from above? (Enter your answer in degrees to at least 2 decimal places.)
16.3
You know the index of refraction for air and the glass, as well as the angle of incidence, ₁. How does Snell's law relate these three variables to the unknown angle of refraction, 0₂? Be sure
that your calculator is in degree mode. °
O
(b) With what angle of incidence, 03, does the ray approach the interface at the bottom of the glass? (Enter your answer in degrees to at least 2 decimal places.)
↑
O
2.00 cm
(c) With what angle of refraction, 04, does the ray emerge from the bottom of the glass? (Enter your answer in degrees to at least 1 decimal place.)
cm
(d) The distance d separates the twice-bent ray from the path it would have taken without the glass in the way. What is this distance (in cm)?
(e) At what speed (in m/s) does the light travel within the glass?
m/s
ns
(f) How many nanoseconds does the light take to pass through the glass along the angled path shown here?
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Step 1: Note and Determine the given values:
VIEWStep 2: Calculate the angle of refraction that describes the ray after it enters into the block
VIEWStep 3: Calculate the angle of incidence at which the ray approaches the bottom of the glass block
VIEWStep 4: Calculate the angle of refraction at which the ray emerges from the bottom of the glass block
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