A random variable X has the following probability distributionX0123Y(X = 3)3K2KK4KThen P(X≥2)=a) 0.1b) 0.2d) 0.5c) 0.4

Answered: A random variable X has the following…

A random variable X has the following probability distribution X 0 1 2 Y(X=3) 3K 2K 21 3 K 4K Then P(X≥2)= a) 0.1 d) 0.5 b) 0.2 c) 0.4

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter13: Probability And Calculus

Section13.CR: Chapter 13 Review

Problem 42CR

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Question

A random variable X has the following probability distribution
X
0
1
2
3
Y(X = 3)
3K
2K
K
4K
Then P(X≥2)=
a) 0.1
b) 0.2
d) 0.5
c) 0.4

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