A random sample of 21 wolf litters in Ontario, Canada, gave an average of x1 = 4.7 wolf pups per litter, with estimated sample standard deviation s1 = 1.0. Another random sample of 7 wolf litters in Finland gave an average of x2 = 2.8 wolf pups per litter, with sample standard deviation s2 = 1.4. (a) Find an 85% confidence interval for ?1 – ?2, the difference in population mean litter size between Ontario and Finland. (Round your answers to one decimal place.) lower limit upper limit (b) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 85% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland? Because the interval contains only positive numbers, we can say that the average litter size of wolf pups is greater in Ontario.Because the interval contains both positive and negative numbers, we can not say that the average litter size of wolf pups is greater in Ontario. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that the average litter size of wolf pups is greater in Finland. (ii) What sampling distribution will you use? What assumptions are you making? The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The standard normal. We assume that both population distributions are approximately normal with known standard deviations.The Student's t. We assume that both population distributions are approximately normal with known standard deviations. What is the value of the sample test statistic? Compute the corresponding z or t value as appropriate. (Test the difference ?1 − ?2. Round your answer to three decimal places.) (iii) Find (or estimate) the P-value.

A random sample of 21 wolf litters in Ontario, Canada, gave an average of x1 = 4.7 wolf pups per litter, with estimated sample standard deviation s1 = 1.0. Another random sample of 7 wolf litters in Finland gave an average of x2 = 2.8 wolf pups per litter, with sample standard deviation s2 = 1.4. (a) Find an 85% confidence interval for ?1 – ?2, the difference in population mean litter size between Ontario and Finland. (Round your answers to one decimal place.) lower limit upper limit (b) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 85% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland? Because the interval contains only positive numbers, we can say that the average litter size of wolf pups is greater in Ontario.Because the interval contains both positive and negative numbers, we can not say that the average litter size of wolf pups is greater in Ontario. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that the average litter size of wolf pups is greater in Finland. (ii) What sampling distribution will you use? What assumptions are you making? The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The standard normal. We assume that both population distributions are approximately normal with known standard deviations.The Student's t. We assume that both population distributions are approximately normal with known standard deviations. What is the value of the sample test statistic? Compute the corresponding z or t value as appropriate. (Test the difference ?1 − ?2. Round your answer to three decimal places.) (iii) Find (or estimate) the P-value.

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter13: Probability And Calculus

Section13.2: Expected Value And Variance Of Continuous Random Variables

Problem 10E

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Question

A random sample of 21 wolf litters in Ontario, Canada, gave an average of x₁ = 4.7 wolf pups per litter, with estimated sample standard deviation s₁ = 1.0. Another random sample of 7 wolf litters in Finland gave an average of x₂ = 2.8 wolf pups per litter, with sample standard deviation s₂ = 1.4.

(a) Find an 85% confidence interval for ?₁ – ?₂, the difference in population mean litter size between Ontario and Finland. (Round your answers to one decimal place.)

lower limit
upper limit

(b) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 85% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland?

Because the interval contains only positive numbers, we can say that the average litter size of wolf pups is greater in Ontario.Because the interval contains both positive and negative numbers, we can not say that the average litter size of wolf pups is greater in Ontario. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that the average litter size of wolf pups is greater in Finland.

(ii) What sampling distribution will you use? What assumptions are you making?

The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The standard normal. We assume that both population distributions are approximately normal with known standard deviations.The Student's t. We assume that both population distributions are approximately normal with known standard deviations.

What is the value of the sample test statistic? Compute the corresponding z or t value as appropriate. (Test the difference ?₁ − ?₂. Round your answer to three decimal places.)

(iii) Find (or estimate) the P-value.

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