A random sample of size 925 is drawn from a large population. The population standard deviation is 12.5. The sample mean is 80.9. Find a 90% confidence interval for the population mean, µ. Round your answers to the nearest tenth. < µ <

Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…

A: Given,population standard deviation(σ)=60margin of error(E)=9α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: The average daily volume of a computer stock in 2011 was μ = 35.1 million shares, according to a…

A: (b) Obtain the 95% confidence interval about the sample mean of stocks traded in 2018. The 95%…

Q: How large a sample should be selected to provide a  95% confidence interval with a margin of error…

A: The formula for the  sample size is as follows: Here, zα/2 is the critical value at 95% confidence…

Q: A sample of size 10 is taken from the population of morel mushrooms and used to calculate an average…

A:

Q: Based on a sample of 180 textbooks at the store, you find an average of 106.02 and a standard…

A: From the provided information, Sample size (n) = 180 Sample mean (x̄) = 106.02 Sample standard…

Q: How large a sample should be selected to provide a 95%  confidence interval with a margin of error…

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Q: A random sample of size n1 = 25 taken from a normal population with standard deviation of 5 has a…

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Q: A random sample of 100 observations is taken from a normal population where the standard deviation…

A: Given, Sample size = 100 Sample mean = 100 Population standard deviation = 40   Since the population…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Population standard deviation, sigma is 50. The z-critical value for 95% confidence interval is…

Q: A random sample of 120 observations produced a mean of x¯=35.7 from a population with a normal…

A: Confidence interval for mean is given by, (X bar + - z*sigma/√n) Z at 95% confidence level is 1.96…

Q: A random sample of 100 observations produced a mean of x¯=37.3 from a population with a normal…

A: GivenMean(x)=37.3standard deviation(σ)=2.05sample size(n)=100

Q: A simple random sample of 60 items resulted in a sample mean of 80. The populationstandard deviation…

A: Sample size = n = 60, Sample mean = = 80, Population standard deviation = s = 15, Confidence…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

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Q: In a random sample of 100 batteries produced by a certain method, the average lifetime was 150 hours…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

Q: When the population standard deviation is unknown and the sample size is less than 30, what table…

A: the population standard deviation is unknown and the sample size is less than 30

Q: A sample of size n=90 is drawn from a population whose standard deviation is σ=10. (A) Find the…

A:

Q: A simple random sample with n = 54 provided a sample mean of 22.5 and a sample standard deviation of…

A: According to the provided information, The 90% confidence interval can be calculated as:…

Q: The standard deviation for a population is sigma = 7.05 . A random sample selected from this…

A:

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given, Margin error (E) = 6 Standard deviation = 20   The objective is to find the sample.…

Q: Consider a population that follows a normal distribution with a known standard deviation o. By what…

A: Confidence interval: It is defined as the range which contains the value of true population…

Q: and sample standard deviation s = 5.9. i. Construct a 95% confidence interval for the population…

A:

Q: A sample of size  n = 10 is drawn from an approximately normal population whose standard deviation…

A: It is given that the sample mean is 50.9 and the population standard deviation is 12.5.

Q: A random sample of 87 airline pilots had an average yearly income of $99,400 with a standard…

A: Let t be the random variable for the average yearly income of airline pilots.  Given that :  The…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Solution: From the given information, σ=10 and E=9. The confidence level is 0.95.

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A:

Q: A random sample of 110 observations produced a mean of x¯=35 from a population with a normal…

A: It is given that a  random sample of 110 observations produced a mean of x¯=35 from a population…

Q: A simple random sample with n= 52 provided a sample mean of 23.0 and a sample standard deviation of…

A: It is given that Sample size n = 52 Sample mean M = 23.0 Sample SD s = 4.7 The critical value of t…

Q: A sample of size n=15 has sample mean "x"=2.1 and sample standard deviation s=1.7. A. Construct a…

A: Given Datan = 15mean µ = 2.1sample standard deviation, s = 1.7 A)95% confidence interval for the…

Q: A statistics practitioner took a random sample of 54 observations from a population whose standard…

A: Given,sample size(n)=54sample mean(x¯)=109population standard deviation(σ)=32

Q: A simple random sample of size n is drawn. The sample mean, x bar, is found to be 18.4, and the…

A: Given that,  = 18.4 s = 4.5 n = 35 Degrees of freedom = df = n - 1 = 35- 1 = 34

Q: suppose x has a normal dist. with a population standard deviation of 2.2. if a random sample size 31…

A: Obtain the margin of error for a 98% confidence interval. The margin of error for a 98% confidence…

Q: The average daily volume of a computer stock in 2011 was μ=35.1 million​ shares, according to a…

A:

Q: The average salary of 81 random employees in a certain financial sector was 3400 USD. From past…

A: Solutio

Q: In a study it was found out of a random sample of 30 there was a sample standard deviation of 2.4.…

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Q: How large a sample should be selected to provide a  95% confidence interval with a margin of error…

A: It is given that the confidence level is 95% and the margin of error is 1. Assumed population…

Q: A random sample of 16 light bulbs has a mean life of 650 hours and a standard deviation of 32 hours.…

A: Mean = mu = 650 Standard deviation = sigma = 32 25.0 Sample size = 16 Therefore standard error of…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A:

Q: a. Find the 95% and 99% confidence intervals for the mean gold content in that area. Assume that the…

A: Here given sample mean = 2.6 grams per ton n = 36

Q: A sample of size n=56 is drawn from a population whose standard deviation is 4.5 Find the margin of…

A:

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given dataStandard deviation = 20Confidence interval = 0.95Significance level(α) = 1- 0.95 = 0.05n =…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given information: Confidence interval(c)= 95%. Margin of error(E)=7. Population standard…

Q: A tire manufacturer investigated the tread life of its tires. Samples of 10 tires driven 50,000…

A:

Q: The average daily volume of a computer stock in 2011 was μ=35.1 million shares, according to a…

A: Given that n=40x¯=31.3s=13.1confidence level=0.95

Q: A simple random sample with n = 54 provided a sample mean of 22.5 and a samplestandard deviation of…

A: Confidence interval give a range of values for the unknown parameter of the population. The width of…

Q: A random sample of size 30 from a normal population yields  = 39  and s = 4.9.  The lower bound of a…

A: Note:Hey there! Thank you for the question. In the first line, it is written “A random sample of…

Q: Based on a sample of 150 textbooks at the store, you find an average of 101.49 an deviation of 17.…

A: NOTE: As per the guidelines, we are supposed to solve first question only. Given:n=150x¯=101.49s=17…

Q: A simple random sample with n = 52 provided a sample mean of 23.5 and a sample standard deviation of…

A: a. The given sample size is 52, sample mean is 23.5, and sample standard deviation is 4.1. The…

Q: A NAPA Auto Parts supplier wants information about how long car owners plan to keep their cars. A…

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Q: A random sample of 55 airline pilots had an average yearly income of $99,000 with a standard…

A: Givensample size(n)=55Mean(x)=99000stadard deviation(σ)=15000

Q: A random sample of 90 observations produced a mean of x = 34.6 from a population with a normal…

A: